The galvanometer is oriented so that the plane of the coil is vertical and aligned along parallel to the horizontal component He of the Earth's magnetic field (i.e. parallel to the local "magnetic meridian"). When an electrical current flow through the galvanometer coil, a second magnetic field H is created. At the center of the coil, where the compass needle is located, the coil's field is perpendicular to the plane of the coil. These two perpendicular magnetic fields add vertically, and the compass needle points along the direction of their resultant He + H. The current in the coil causes the compass needle to rotate by an angle\ \theta.
because in tangent galvanometer earth magnetic field and magnetic field of magnet inside galvanometer are perpendicular to each other
by using the formula b=μn/2A(I/TAN Ɵ)....where μ=4πx10 pow(-7)n=number f turns of the coilA=radius of the coil(m)I=current flowing through the coil(A)Ɵ=angle of deflection in the tangent galvanometer.
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The expression for tan @ is F/B Here F = mu not n I / 2a mu not = permiability of air which equals to 4pi x 10-7 H/m n = number of turn in the TG a - radius of coil in TG in meter I = the current flowing through in ampere B is the earth's magnetic field. Hence B = F / tan@ Here @ is the angle of deflection in the TG when two perpendicular fields are applied. Here one is earth's magnetic field whose induction is B tesla and F is the magnetic field produced due to flow of current in the TG coil
yes,the direction of electric force on a charge is tangent of field lines.
it is the current measured in amphere..
to detect the sudden change in current.
because in tangent galvanometer earth magnetic field and magnetic field of magnet inside galvanometer are perpendicular to each other
IG=Betanx. in this G is G.constant, I is current, Be is Megnetic field of earth, OK? or anything else?
Reduction factor of the tangent galvanometer is actually numerically equal towards the current in ampere needed to produce a deflection of 45° in it whenever the plane of the coil lies together the magnetic meridian.
We find it by varying the current flowing through it and by measuring the deflection respectively and then we use the formula k=I/tan(theta)
reduction factor is used to find earth's magnetic field and compare galvanometer constants
by using the formula b=μn/2A(I/TAN Ɵ)....where μ=4πx10 pow(-7)n=number f turns of the coilA=radius of the coil(m)I=current flowing through the coil(A)Ɵ=angle of deflection in the tangent galvanometer.
application of Ballistic Galvanometer 1) measurements of electric charges
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1) to calculate coeficient of error 2) to calculate deviation between the readings to infere a behaviour
You mean 'K' in the formula for current, measured by tangent galvanometer! Then, ampere is the unit. Because I = K tan(theta) Tan (theta) is just a ratio of distances ie opposite side distance and adjacent side length. So no unit for tan. Left side, ampere is the unit for I (current) BY the homogeneity of dimensions, both side must have the same dimension (or unit) Therefore K must have ampere as unit.