The calorific value of water is 80cal/degree. so it takes 60*80=2400cal of heat.
The heat required to evaporate 1 liter of water at 100 degrees Celsius is known as the latent heat of vaporization of water, which is approximately 2260 kJ/kg. Since the density of water is about 1000 kg/m³, the heat required would be around 2260 kJ.
Due to more volume mass, it will take longer, but the 2 liters with double mass will eventually heat up the same 10 FIVE degrees with the same energy amount.
1 quart an hour 1 liter
To heat 1 gram of water by 1 degree Celsius, it takes 4.18 joules. So, to heat water from, for example, 20 degrees to 100 degrees, you would need to calculate the total mass of water and apply the specific heat capacity to determine the total energy required.
A liter of pure water weighs at most 1 kilogram (at 4 degrees Centigrade). This is about 2.2 pounds. Water at higher temperatures is less dense and will weigh slightly less.
To raise 1000 grams of water from 50 to 100 degrees requires 50 degrees x 1000 grams of heat, so the answer is 50,000 calories. Water at 100 degrees requires an additional 550 calories to convert 1 gram fully into steam. Therefore the remaining 50,000 calories can convert 50,000/550 grams into steam. So 90.9 grams become steam, and that's the answer.
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The amount of propane needed to heat a 50 gallon water heater from 75 degrees to 105 degrees would depend on factors such as the efficiency of the water heater, the starting temperature of the water, and the ambient temperature. It is difficult to provide an exact amount without this information.
6.276 kJ
To calculate the energy needed to change ice at -32.9 degrees to water at 75 degrees, you need to consider the energy required for three steps: Heating ice from -32.9 degrees to 0 degrees (specific heat capacity of ice) Melting ice at 0 degrees into water at 0 degrees (latent heat of fusion of ice) Heating water from 0 degrees to 75 degrees (specific heat capacity of water) Once you have the energy needed for each step, you can add them together to find the total energy required.
This happens because there is so much more water than there is horseshoe. The heat from the horseshoe is distributed throughout the water, so the amount of heat per unit of water is lower than the original amount of heat per unit of horseshoe.
1 liter