Calculus

the sum of -5 and 3x

2x-3 = 21+10x

2x-10x = 21+3

-8x = 24

x = -3

2x + 5 = -76 - 7x

Add 7x to both sides: 9x + 5 = - 76

Subtract 5 from both sides: 9x = -81

Divide both sides by 9: x = -81/9 = -9

In 7x+7, x is a variable.

5x + 2 = x + 12

5x - x = 12 - 2

4x = 10

x = 10/4

x = 5/2 or 2.5

They add up to: 8x2

An equation.

72-4*4*4 = -15

The discriminant is less than zero so there's no solutions to the quadratic equation.

x² + y² - 4x + y - 1 = 0

( x² - 4x ) + ( y² + y ) = 1

( x² - 4x + 4 ) + [ y² + y + (1/4) ] = 1 + 4 + (1/4)

( x - 2 )² + [ y + (1/2) ]² = [ √(21) / 2 ]²

This equation represents a Circle with

Centre ≡ ( 2, -1/2 ) and Radius = √(21) / 2.

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Piece wise functions can do everything. Take two pieces of two rational functions, one have a horizontal asymptote as x goes to -infinity and the other have a slanted (oblique) one as x goes to +infinity.

It is still a rational function.

2y - x = 3

y = -5x + 7

Rewrite the second

y + 5x = 7

Mutiply it by 2

2y + 10x = 14

Now subtract the first equation from this:

2y + 10x = 14

2y - x = 3

11x = 11

Divide both sides by 11: x = 1

Substitute for x in the first equation:

2y - 1 = 3

Add 1 to both sides: 2y = 4

Divide both sides by 2: y = 2

Answer: (x, y) = (1, 2)

When x = -2 then y = 4 which is the common point of intersection of the two equations.

Some of the operands are missing (due to limitation of editor?) and hence assuming the equation is x^2+5x-5 = 0. The roots are

(-5 + sqrt(25+20))/2 and (-5 - sqrt(25+20))/2

(-5 + sqrt(45))/2 and (-5 - sqrt(45))/2

(-5 + 6.70)/2 and (-5 - 6.70)/2

(1.70)/2 and (-11.70)/2

0.85 and -5.85

73474949444999272725678251628909813.345267777777776663

x2+12x+5 = 3

x2+12x+5-3 = 0

x2+12x+2 = 0

Yes.

y = kn / (1 + n2)

First, let's express it with negative exponents:
y = kn * (1 + n2)-1

Then apply the chain rule:
dy|dn = k(1 + n2)-1 - kn(1 + n2)-2 * 2n

And simplify:
dy|dn = k / (1 + n2) - 2n / kn(1 + n2)

2250000000

x = (y-b)/m

x=6=x=5+x=13+x=20

x cannot = x+5. This question has no answer.

Get x on it's own so 8x = x -4 would become

7x = -4

x = -0.57

y = 12x + 5x - 7

Since '12x' and '5x' both have the same variable, you are able to combine them. To do this you just need to add 12 + 5 to get 17.

After doing this you can rewrite the equation as y = 17x - 7.

You can then solve this equation for different values by plugging in a number for 'x' or 'y' or graphing the equation.

It can be considered a philosophical question, without any real answer.

But the easiest answer to this question is to consider the fact that an infinity is an infinity and have a beginning but no end. Then every infinity would have beginnings but no ends, so no matter how many you have, every infinity would still be equal to oneanother.

It could resemble a pie with roughly 1/4 of it missing.