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Probability
The probability of a certain event is a number expressing the likelihood that a specific event will occur, expressed as the ratio of the number of actual occurrences to the number of possible occurrences. In mathematics, it is a measure of how often an event will happen and is the basis of statistics.
14,643 Questions
What is the shape of this distribution?
A company is studying the number of daily debit card purchases. If there were 20 purchases and the probability of a debit card purchase is 0.5
What is the shape of this distribution
A three digit number can be chosen in 9*10*10 = 900ways
No. of ways to choose a three digit number without 7 is 8*9*9 = 648 ways
probability of picking a three digit number that includes atleast one digit that is 7 is 1- (648/900) = 252/900 = 7/25
Why is sample size important in determining probability?
The bigger the sample size the more accurate the results will be.
For example, if you roll a 6 sided die and track the results to get the probability of rolling a six. If you only roll 6 times, then you may not even get one 6 or you could get a few. A small sample size means you won't get very reliable results.
idk i wish that some would tell me lol COOKIE all day HHS HASS PROGRAM
What is the probability that you will guess the same number that the computer chose in one try?
The probability depends on the range of numbers from which to choose.
If there is no limit to the range then probability is incalculable.
0 (there is no chance it will be short since tall is dominant over short).
Hope this helps!
- Biology Student
What is the product rule and the sum rule of probability?
Sum Rule:
P(A) = \sum_{B} P(A,B)
Product Rule:
P(A , B) = P(A) P(B|A) or P(A, B)=P(B) P(A|B)
[P(A|B) means probability of A given that B has occurred]
P(A, B) = P(A) P(B) , if A and B are independent events.
What is the probability that a child will have a round face brown or blond hair?
Depends on the parents.
The probability of getting heads twice and tails once if a coin is tossed 3 times?
3/8, or 37.5%
There are eight possible sequences that can emerge from three coin tosses. Three have heads twice and tails once. Three have the opposite, two tails and one heads. The remaining possibilities are all heads or all tails.
- H H T
- H T H
- T H H
- T T H
- T H T
- H T T
- H H H
- T T T
Why can't the probability of an event occurring be greater than 1?
If probability becomes greater than one, then the uncertainty coefficient fluctuates and results in a terminal case.
The answer would be 2/11 plus 1/2. Whatever that is.
If two fair dice are rolled what is the probability of rolling a double given that the sum was 11?
Let A = rolling a double Let B = sum is 11 P(A)=6/36=1/6 P(B)=2/36=1/18 since (5,6) and (6,5) produce a sum of 11. We want to find P(A/B)= P(A & B) / P(B) = 0 / P(B)=0 P(A & B) represent the event getting a double and the sum being 11.
A 50% to 50% chance (half to half).
What are the chances for dissipation of small amounts of fluid around lungs?
If there is a small pleural effusion the treatment of the underlying cause will reverse the process allowing the fluid to recede back into the parenchyma of the lungs. Normally this is the case with CHF patients that have pulmonary edema. Right sided heart failure causes a fluid buildup that can go as far as the pleural space.
risk
Six face cards have been removed leaving 46 cards. 1) There are 2 quees left. P( queen) = 2/46 = 1/23 2)There are 20 red cards left. P( red card)=20/46=10/23 3) There are 26 spade cards left. P( spade card)=26/46 =13/23
How do you work out the mean in maths?
add up all the numbers you have then divide by the amount of numbers you have
The mean is the same as the average. You must add up all the data, then divide by the number of data entries you added. E.g. 3+5+2+6+4=20 then 20 divided by 5 = 4, so in this case 4 is the mean.
If a fair six sided die was rolled 4 times what is the probability of getting at least one ace one?
p(one) = 1/6
p(not one) = 5/6
p(at least one) = 1 - p(failure)
p(failure) = (4C0)(5/6)^4 = 1 x 625/1,296 = 0.48
p(at least one) = 1 - 0.48 = 0.52
false
How do you teach probability of independent events?
Two events are said to be independent if the result of the second event is not affected by the result of the first event. Some common ways to teach this are to perform simulations with coin flips.
Students need to understand that if A and B are independent events, the probability of both events occurring is the product of the probabilities of the individual events.
Students can predict and then observe probabilities of a fixed number of heads or tails.
This lets then see the ideas in action.
How do you use square roots on your TI-30X IIS calculator?
Well i had the same qustion first u press 2nd then you press the button that looks like this ^ then put your number inexample: 3 2nd ^ 78 it would be 4.272658682
all that matters in this problem, is that 2 of the 13 spaces are orange.
On the first spin, the odds are 11:2 against Jake getting the orange space.
On the second spin, the result of the first spin has no relevance or influence at all, so the odds are still 11:2 against.
Why is this question flagging up in "breakups"?
