Probability

The probability of tossing a coin twice and getting tails both times is 1 in 4, or 25%.

If you have already tossed a coin and had it land on tails, the probability that it will land on tails again the next time you toss it is 50%.

If p is the probability that an event will happen once, then the probability that it will happen just twice is p2. The probability it will happen 3 times is p3. The probability it will happen at least once ( ie once or twice or three times ore more times is p + p2 + p3 + ... = p(1-p). For "or" you add probabilities, for "and" you multiply probabilities.

I'm assuming this is a combinations problem.

nCk = n!/(k!(n-k)!) is the general equation.

In your case n= 11 and k = 5

for 11!/(5!(11-5)!) = 11!/(5!*6!) = (11*10*9*8*7)/(5*4*3*2*1) = 462

Yes.

Number of cards in a deck = 52

Number of cards that are spade = 13

Number of cards that are heart = 13

Probability that the card drawn is a spade and heart =

13/52 + 13/52

= 26/52 or 1/2

The probability of an even must be a real number in the range [0, 1]. 120% is outside that range.

Two events are equally unlikely if the probability that they do not happen is the same for each event. And, since the probability of an event happening and not happening must add to 1, equally unlikely events are also equally likely,

P(Winning) = 50/700 = 0.0714... ≈ 7.14 %

the mishap probability component is an estimation that a hazard will result in a mishap

Simple random sampling.

Logical decision making. Gambling. Odds.

When two dice are rolled, the probability of getting:

2 is 1/36

3 is 2/36

4 is 3/36

5 is 4/36

6 is 5/36

7 is 6/36

8 is 5/36

9 is 4/36

10 is 3/36

11 is 2/36

12 is 1/36

Let sigma = standard deviation.

Standard error (of the sample mean) = sigma / square root of (n), where n is the sample size. Since you are dividing the standard deviation by a positive number greater than 1, the standard error is always smaller than the standard deviation.

It simply means that you have a sample with a smaller variation than the population itself. In the case of random sample, it is possible.

1 in 26

If the digit 0 is allowed then the answer is 1/(10*9*8) = 1/720 = 0.0014 approx.

If 0 is disallowed, then 1/(9*8*7) = 1/504 = 0.0020 approx.

If you roll the die often enough, the probability of getting a 2 ones in a row is 1.

In only 2 rolls, the answer is (1/6)*(1/6) = 1/36

80 percent percent = 0.008. The two tailed z-score for 0.008 is 2.652

The binomial distribution has two parameter, denoted by n and p.

n is the number of trials.

p is the constant probability of "success" at each trial.

the probibility of drawing a heart diamond or a spaid is a 1/3 chance........

Number of cards in a deck =52

Number of cards that are spade =13

Number of cards that are eight =4

Number of cards that are spade and eight =1

Probability that the card drawn is a spade or an eight =

13/52+4/52 -1/52

=16/52 or 4/13

Theoretical probability.

20, without replacing the first book chosen.

25 with replacing it.