How do you test the normality of a random variable?
There are various goodness-of-fit tests. The chi-square and Kolmogorov-Smirnoff tests are two of the better known of these.
Your name is harsh saxena you lost your roll number of upseat 2010 can you get dat back?
Possibly, but not from this site!
What is the probability of obtaining getting a number greater than 4 when rolling a single die once?
Since there are two numbers greater than 4 on a six sided die (5 & 6), the numerator of your fraction is 2. There are six possibilities in total (1, 2, 3, 4, 5,6), so that's your denominator. Your fraction will end up being 2/6, simplified it will be 1/3 or 1 out of 3.
You would REALLY first need to find out what percentage of M&Ms are red. Since the sample is quite large, if this base percentage (as a ratio) is quite a bit lower than 0.165, then the probability you ask for is almost zero; if the ratio is quite a bit larger than 0.165, the probability you ask for will be almost 1 (i.e., 100%); only if the base probability is very close to 0.165 would you get more "interesting" results.
If we are testing a hypothesis about the population mean , if none of the conditions of using a z-score or the conditions for using a t-score are met, we may use a proper non-parametric test.
How many people have birthday on nov 11 2011?
None, since, as of nov 4, 2011, nov 11, 2011 has not yet occurred.
Which is farther west eastern standard centeral standard mountain standard and pacific standard?
Pacific time zone is the farthest West.
If you toss a die 300 times what is the standard error for the expected number of threes?
It is 6.45, approx.
From a pile of 10 blank copy books which are alike in how many ways can you pick 5 of them?
10!/5!x5!
3,628,800/14,400
252.
There are 252 ways.
Why is the probability meter labeled with fraction decimals and percents?
So it can be used for a number of different kinds of math problems
What do you know about 2 dice being rolled?
You know that the sample space of one die being rolled is
{1,2,3,4,5,6}, if you roll two dice,
you have a sample space with 36 elements. Here it is: (1,1)(1,2)(1,3)(1,4)(1,5)(1,6)(2,1)(2,2)(2,3)(2,4)(2,5)(2,6)(3,1)(3,2)(3,3)(3,4)(3,5)(3,6)(4,1)(4,2)(4,3)(4,4)(4,5)(4,6)(5,1)(5,2)(5,3)(5,4)(5,5)(5,6)(6,1)(6,2)(6,3)(6,4)(6,5)(6,6)
From this we can calculate many probabilities. We could look at the sums. For example what is the probability of rolling two dice and have a sum of 2?
There is only one way out of 36 for this to happen so it is 1/36.
Similarly, what is the chance of rolling a 1 and a 3, in either order?
What is the chance of having a sum of 6? All these answers come directly from
the sample space above.
Name Three possible outcomes of obesity?
Diabities, blood clot, being made fun of, embarrassment, appearance ect.
What is the ratio of 18 blue marbles to 20 green marbles?
18:20 reduces to 9:10 if you divide both sides by 2
How come you do not need to have three actual coins to compute the probabilities for these outcomes?
Because the theory of coin flipping is well understood and so theoretical probabilities can be used.
What is the standard deviation of a sample of 35 25 36 42 37?
Putting the data into excel, the std dev for the sample is 6.20
How many distinct three letter arrangements can be found from the letters in mathematics?
The number of different three letter arrangements that can be done from the
letters in the word "mathematics"
is; 11P3 =
11!/(11-3)! =
990