Calculus

z = 2

Factorised as (z - 2)(z - 2) = 0

Addition is commutative

Yes, that is correct.

The result obtain from the equation 4 plus -1 -21 is -18.

are you sure from this equation ?

x^2 + 9x + 11

____________ = zero

x + 7

or there is no zero ??

please be sure from the x^2 + 9x + 11 ???

If you mean Microsoft's backup file extension, it's function is to make PCs and Macs even more incompatible, thus putting more money into Bill Gates' pocket.

Y. B. Mokashi has written:

'Prakshobha'

(956 - 830) x (908 x 291 + 598) =

(126) x (264228 + 598) = 33368076

1.5/6.5 = 3/13 and 6.5/1.5 = 13/3

The equation is : 39x2 - 178x + 39 = 0

x = {-(-178) ± sqrt[(-178)2 - 4*(39)*(39)]}/(2*39)

= {178 ± sqrt[25600]}/78

= {178 ± 160}/78

= 18/78 or 338/78

= 3/13 or 13/3, as required.

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This is what I would add, although it might be unnecessary:

As Mehtamatics indicates the solutions are 3/13 and 13/3. This implies that the equation can be written as the product of factors ( x - 3/13 ) and ( x - 13/3 ).

( x - 3/13 )( x - 13/3 )

= x2 - ( 39 + 169 ) x / 39 + ( 3/13 ) ( 13/3 )

= x2 - 178 x / 39 + 1

= 39 x2 - 178 x + 39 = 0

The required condition is a*b ≠ 0. That is equivalent to the requirement that neither a nor b is 0.

Following are the conditions for one to one function

1. If range f=B.

2. Every element in set A has one image and steB also has only One element corresponding to it.

Unfortunately, the browser used by Answers.com for posting questions is incapable of accepting mathematical symbols. This means that we cannot see the mathematically critical parts of the question. We are, therefore unable to determine what exactly the question is about and so cannot give a proper answer to your question. Please edit your question to include words for symbols and any other relevant detail.
It appears that there are some symbols missing in the equations.

9x plus 3 plus 2x plus 1 will result to 11x+4(first collect the like terms).

The answer is the infinite set of coordinates, each of which represents a point of the line given by the equation.

-x -2 = 2

so -x = 2+2 = 4

and so x = -4

Change the '5' to a smaller number.

do the 2nd equation first and use the answer for the 1st one (5x-2=n and then 3x+6=n)

1

It is not possible to solve a single linear equation in two variables.

ordered pair, or coordinates of a point

Solution

Given the limitations of the browser that is used by this site, it is difficult to be certain about your question. If I misunderstand your question, (a) please accept my apologies and (b) resubmit your question spelling out the symbols as "plus", "minus", "times", "equals", "squared", "cubed" etc.

I am assuming that you wish to solve e2x = 3x2

The only way that I can think of solving this is numerically and, in that case, the Newton Raphson method is quick and easy (for differentiable functions).

To start with, your question is equivalent to finding a solution to e2x - 3x2 = 0, so define f(x) = e2x - 3x2.

Therefore f'(x) = 2e2x - 6x.

Start with x0 as the first guess.

Then let xn+1 = xn - f(xn)/f'(xn) for n = 0, 1, 2, …

Continue until you get convergence of xn.

If you plot a graph of f(x) against x, you will know that the root of f(x) lies between -1 and 0. This helps to select a suitable value for x0.

If you start with -1, your error is around 8 per billion at x4. If you start with 0, it is less than 1 in 1.5 billion at x4. The answer is -0.390646381 (approx).

x = (-1 ± √11) / 2

It is 2 terms of an algebraic expression in the form of: 3x+731

8.37