Calculus

The required condition is a*b ≠ 0. That is equivalent to the requirement that neither a nor b is 0.

1.5/6.5 = 3/13 and 6.5/1.5 = 13/3

The equation is : 39x2 - 178x + 39 = 0

x = {-(-178) ± sqrt[(-178)2 - 4*(39)*(39)]}/(2*39)

= {178 ± sqrt[25600]}/78

= {178 ± 160}/78

= 18/78 or 338/78

= 3/13 or 13/3, as required.

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This is what I would add, although it might be unnecessary:

As Mehtamatics indicates the solutions are 3/13 and 13/3. This implies that the equation can be written as the product of factors ( x - 3/13 ) and ( x - 13/3 ).

( x - 3/13 )( x - 13/3 )

= x2 - ( 39 + 169 ) x / 39 + ( 3/13 ) ( 13/3 )

= x2 - 178 x / 39 + 1

= 39 x2 - 178 x + 39 = 0

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9x plus 3 plus 2x plus 1 will result to 11x+4(first collect the like terms).

x = (-1 ± √11) / 2

do the 2nd equation first and use the answer for the 1st one (5x-2=n and then 3x+6=n)

1

It is not possible to solve a single linear equation in two variables.

ordered pair, or coordinates of a point

It is 2 terms of an algebraic expression in the form of: 3x+731

Following are the conditions for one to one function

1. If range f=B.

2. Every element in set A has one image and steB also has only One element corresponding to it.

Given the limitations of the browser that is used by this site, it is difficult to be certain about your question. If I misunderstand your question, (a) please accept my apologies and (b) resubmit your question spelling out the symbols as "plus", "minus", "times", "equals", "squared", "cubed" etc.

I am assuming that you wish to solve e2x = 3x2

The only way that I can think of solving this is numerically and, in that case, the Newton Raphson method is quick and easy (for differentiable functions).

To start with, your question is equivalent to finding a solution to e2x - 3x2 = 0, so define f(x) = e2x - 3x2.

Therefore f'(x) = 2e2x - 6x.

Start with x0 as the first guess.

Then let xn+1 = xn - f(xn)/f'(xn) for n = 0, 1, 2, …

Continue until you get convergence of xn.

If you plot a graph of f(x) against x, you will know that the root of f(x) lies between -1 and 0. This helps to select a suitable value for x0.

If you start with -1, your error is around 8 per billion at x4. If you start with 0, it is less than 1 in 1.5 billion at x4. The answer is -0.390646381 (approx).

Solution

8.37

sqare root of 145. my approximation... 12.0398 cm

There is none, it continues to multiply and go on and on.

A = 3.14(Pi) x r2 So, if radius is 4 inches, then A = 3.14 x (4 in. x 4 in.)

A = 3.14 x 16

A = 50.24 in. 3.14 is just an approximation to Pi of course, we could use more digits of Pi if we need it.

When pi is written digitally, it never ends and never repeats, because it is an infinite number.

This is just the beginning, though: 3.14159265358979323846…

3

The answer depends on 1 billion WHAT! And since you have not bothered to share that crucial bit of information, I cannot provide a more useful answer.

most likely 18

It depends on what you are trying to solve for. Here is a solution for x... y = mx + b y - b = mx (y - b) / m = x Note: If m is zero, then there is no solution, because the line is horizontal

Each side can have any length in the range (0, 12.9) units. The only restriction is that the sum of the seven sides must be 12.9 units.

If x+8=8, then x=0.

No its 16