If something measures 23.3 in x 17.4 in x 6.95 in what is its cube?
This question does not make sense. An object with different measurements for length , breadth and height cannot be a cube. And if the measurements are not l, b and h but something else then there is no way of calculating the size of the object.
What is the greatest common factor of 16 60 and 90?
How many millimetres are there in 400 centimeters?
There are 10 millimetres in one centimetre. Therefore, 400 centimetres is equal to 400 x 10 = 4000 millimetres.
'3x' means 'three times', and '4x' means 'four times'. '4x' is obviously rather greater than '3x', but neither will bring an object ten miles away into your back garden.
How do you factorise x²-4 plus 3?
I am thinking you must mean x^2-4x+3 otherwise it would be x^2-1 which would factor as (x+1)(x-1).
In any case, it factors as (x-3)(x-1). Just look at the last number, 3 and note it has factors 3 and 1. Now need those factors to add up to -4 and their product to be positive. We must pick -1 and -3.
How do you solve 2- bracket y plus 2 bracket equals 3y?
2 - (y + 2) = 3y
Remove brackets: 2 - y - 2 = 3y
Combine like terms: 0 = 4y
Divide both sides by 4: 0 = y
It is an expression in the variable y.
Since it is not an equation it cannot be solved.
-- At the z-intercept, x=0, y=0, cz=d, so z=d/c.
-- At the x-intercept, y=0, z=0, ax=d, so x=d/a.
The distance between the two points is sqrt[ (d/c)2 + (d/a)2 ] or d sqrt[ (1/c)2 + (1/a)2 ].
Is the following equation solvable - y equals y plus x?
If y = y + x then x must be 0
Otherwise the equation is meaningless.
What can infinity be used for?
One must be careful when using infinity in math. Infinity is a concept - not a value. Sometimes, we may be tempted to try treating infinity as a value or a variable. Whenever we want to use infinity in math, we generally do so through the concept of limits.
For example, instead of saying:
1/∞ = 0
We instead say:
lim 1/x = 0
x→∞
The use of limits allows us to use infinity without falling into the trap of attempting to do arithmetic with infinity, which is not defined. In calculus, we use limits and L'Hopital's rule to get around this, and allows us to evaluate functions which simplify to an indeterminate form (0/0, ∞/∞, 0*∞, 0^0, ∞^0 and ∞ - ∞).
Sometimes we seemingly treat infinity as a value when describing asymptotes or end behavior of a function, for example:
lim 1/x = ∞
x→0+
It is important to realize that we are not saying that 1/0 = ∞, but we are ACTUALLY saying:
"As x approaches 0 from the right, 1 / x approaches infinity."
If you mean solve for X:
3x + 52x + 1 = 0
55x = -1
x = -0.02
What does X equals in this problem X squared plus 4 equals 0?
If we start with x2 + 4 = 0, the next conclusion is that x2 = -4. All real numbers have a positive result when multiplied by themselves, so therefore we are dealing with an imaginary number. The square root of minus four is 2i.
What are the possible values for x if x 5x6?
Unfortunately, limitations of the browser used by Answers.com means that we cannot see most symbols. It is therefore impossible to give a proper answer to your question. Please resubmit your question spelling out the symbols as "plus", "minus", "equals" etc. And using ^ to indicate powers (eg x-squared = x^2).
You look them up in log tables, or use a scientific calculator. The calculators use a method based on the Taylor series.
How do you solve the equation negative 3 cos t equals 1 in the interval from 0 to 2 pi?
Isolate cos (t): cos(t)=1/3. Use a calculator from here because the answer is not an integer or a simple number.
What is the coordinates of 5x plus 5y equals 30 and 3x-5y equals -30?
The given expressions are:
5x + 5y = 30
3x - 5y = -30
Combine both equations to get:
5x + 3x + 5y - 5y = -30 + 30
8x = 0
Then:
8x/8 = 0/8
x = 0
Substitute that value for either of the expressions to get:
5(0) + 5y = 30
5y = 30
y = 30/5
y = 6
Therefore, the coordinates are x = 0 and y = 6.