How do you solve this equation 9 equals 6s?
9 is equal to 6 times x. divide both sides by 6 to leave the x by itself. 9 divided by 6 is 1.5 so x is 1.5.
Algebra and calculus
Start with the first equation: 8=2x-6 so 14=2x so x=7
Now insert the answer for x into the second equation:
So y=2(7)-6 so y=14-6 so y=8
So at a certain point x=7 and y=8 so a coordinate would be (7,8)
The given equation can be simplified to 2x + 3y = 6 but that is about it.
Given 2 unknown variables (x and y) you need two independent equations to solve for them. The only other thing you can so with the above equation is to express
y in terms of x : y = (6 - 2x)/3 = 2 - 2x/3
or
x in terms of y: x = (6 - 3y)/2 = 3 - 3y/2
Both different (and possibly clumsier) ways of saying the same thing as the original equation.
x=3
That wasn't hard at all.
5x-10=-7+4x
-4x -4x
_____________
x-10=-7
+10 +10
_____________
x=3
3x + y = 3
2x - y = -1
Add the two equations: 5x + 0y = 2 or x = 2/5 = 0.4
Substitute the value of x in the first equation: 1.2 + y = 3 so y = 3 - 1.2 = 1.8
If f(x) -7x plus 5x2 plus 10 what does f(-2) equal?
Given f(x) = - 7x + 5x^2 + 10
So f(-2) = - 7(-2) + 5 (-2)^2 + 10 = 14 + 20 + 10 = 44
What is x when y is 30 if x is 20 when y is 40?
x and y are in a ratio of 1:2 so when y is 30 x is 15
What is the derivative of e-3x?
f'(x)=-3
the derivative of e is zero because its a constant. Derivative of -3x is -3. Bring the exponent of x down in front of the -3 and subtract the original exponent by 1. Ex. -3(1...which is the first exponent of the x)x^0(n-1 or 1-1=0)
all this is -3(1)x^0
x^0 is 1 so the derivative of -3x is -3