Start with the first equation: 8=2x-6 so 14=2x so x=7
Now insert the answer for x into the second equation:
So y=2(7)-6 so y=14-6 so y=8
So at a certain point x=7 and y=8 so a coordinate would be (7,8)
x=3
That wasn't hard at all.
5x-10=-7+4x
-4x -4x
_____________
x-10=-7
+10 +10
_____________
x=3
If f(x) -7x plus 5x2 plus 10 what does f(-2) equal?
Given f(x) = - 7x + 5x^2 + 10
So f(-2) = - 7(-2) + 5 (-2)^2 + 10 = 14 + 20 + 10 = 44
If Y = y, then it is 9y4 or 9Y4. If Y is not the same as y, then you can't simplify it any.
How do you solve four to the x power minus two to the x plus one power all equaling 15?
So you have (4^(x-2))^(x+1)=15. Using a law of exponents (b^a)^c=b^(a*c) and 4=2^2, you get
4^((x-2)*(x+1))=15=2^(2(x-2)(x+1)).
Take log base two and use the rule about logs of products you get
2(x-2)(x+1)=Log_2(15)
Simplifying and substituting u for Log_2(15),
2x^2-2x-4=u, which means
2x^2-2x-(4+u)=0, using quadratic formula.
X=(1/4)(2(+or-)sqrt(4-4*2*(-4-u))) or
(1/2) plus or minus (1/4)(sqrt(36+8u))
Where sqrt(b) is the square root of b
What is the derivative of e-3x?
f'(x)=-3
the derivative of e is zero because its a constant. Derivative of -3x is -3. Bring the exponent of x down in front of the -3 and subtract the original exponent by 1. Ex. -3(1...which is the first exponent of the x)x^0(n-1 or 1-1=0)
all this is -3(1)x^0
x^0 is 1 so the derivative of -3x is -3
-4x - 1 = -7
add 1 to both sides to get...
-4x = -6
divide both sides by -4 to get
x = 1.5
What is 5x plus 35 equals -30?
Start by subtracting 35 from both sides to get 5x = -65
Now, divide both sides by 5 to get x = -13
If: 2x+y = 1 then y =1-2x and y^2 = (1-2x)^2 which is 1-4x+4x^2
If: x^2 -xy -y^2 = -11 then x^2 -x(1-2x) -(1-4x+4x^2) = -11
Expanding brackets: x^2 -x +2x^2 -1 +4x -4x^2 = -11
Collecting like terms and adding 11 to both sides: -x^2 +3x +10 = 0
Dividing all terms by -1: x^2 -3x -10 = 0
Completing the square: (x-3/2)^2 -9/4 -10 = 0 => (x-3/2)^2 = 49/4
Square root both sides: x-3/2 = -/+ 7/2
Add 3/2 to both sides: x = 3/2 -/+ 7/2
Therefore: x = 5 or x = -2
Solutions by substitution are: (5, -9) and (-2, 5)