Calculus

Yes.

y = kn / (1 + n2)

First, let's express it with negative exponents:
y = kn * (1 + n2)-1

Then apply the chain rule:
dy|dn = k(1 + n2)-1 - kn(1 + n2)-2 * 2n

And simplify:
dy|dn = k / (1 + n2) - 2n / kn(1 + n2)

2250000000

x = (y-b)/m

Get x on it's own so 8x = x -4 would become

7x = -4

x = -0.57

I see something like this and I use the quadratic formula, which solves all quadratic equations. Discriminant, by inspection, looks good for two real roots.

X = -b +/- sqrt(b^2 - 4ac)/2a

a = -3

b = -1

c = 2

X = -(-1) +/- sqrt[(-1)^2 - 4(-3)(2)]/2(-3)

X = 1 +/- sqrt(25)/-6

X = {1 +/- 5}/-6

X = -1

X = 2/3

My TI-84 confirms these values for X

If 6 +2=8 then 8 =6+2

I think...

but then it could also be 4+4 =8

hope I helped :)

y = 12x + 5x - 7

Since '12x' and '5x' both have the same variable, you are able to combine them. To do this you just need to add 12 + 5 to get 17.

After doing this you can rewrite the equation as y = 17x - 7.

You can then solve this equation for different values by plugging in a number for 'x' or 'y' or graphing the equation.

It could resemble a pie with roughly 1/4 of it missing.

To solve a quadratic equation (which means to find the zeros of that equation) you have two options

1. type the equation into a graphing calculator and graph the resulting equation and find where the x intercepts are (where y=0)

2. solve the quadratic equation by factoring

First, set the equation equal to zero.

x2-8x-9=0

Then find the resulting x values by "smiling"

multiply the first term and the last term (x2) (9)

find two numbers that add to -8 and multiply to -9

these two numbers are -9 and 1

x2- 9x 1x-9

x(x-9) 1(x-9)

the resulting factors are 0= (x+1)(x-9)

to find the roots, set these factors = 0

x+1=0

x=-1

x-9=0

x=9

Therefore, the solutions for the quadratic equation are x=-1 and x=9

x2+12x+5 = 3

x2+12x+5-3 = 0

x2+12x+2 = 0

3x + 2x = 5x

logbase5 of x =z

x=5^z

It can be considered a philosophical question, without any real answer.

But the easiest answer to this question is to consider the fact that an infinity is an infinity and have a beginning but no end. Then every infinity would have beginnings but no ends, so no matter how many you have, every infinity would still be equal to oneanother.

i know you add x to x and y to y but not x to y or y to x

so i answer the exponents and get 334y over 225y times 13824x

324y

----------------

225y 13824x

so i think that you would have to divide 324y by 225y and get 1.44

so if i am right you get

1.44 y 13824 x

They add up to: 8x2

An equation.

5x + 2 = x + 12

5x - x = 12 - 2

4x = 10

x = 10/4

x = 5/2 or 2.5

When x = -2 then y = 4 which is the common point of intersection of the two equations.

8

x² + y² - 4x + y - 1 = 0

( x² - 4x ) + ( y² + y ) = 1

( x² - 4x + 4 ) + [ y² + y + (1/4) ] = 1 + 4 + (1/4)

( x - 2 )² + [ y + (1/2) ]² = [ √(21) / 2 ]²

This equation represents a Circle with

Centre ≡ ( 2, -1/2 ) and Radius = √(21) / 2.

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Happy To Help !

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Piece wise functions can do everything. Take two pieces of two rational functions, one have a horizontal asymptote as x goes to -infinity and the other have a slanted (oblique) one as x goes to +infinity.

It is still a rational function.

That system of equations has no solution. When the two equations are graphed,

they turn out to be the same straight line, so there's no such thing as a single

point where the two lines intersect. There are an infinite number of points that

satisfy both equations.

Some of the operands are missing (due to limitation of editor?) and hence assuming the equation is x^2+5x-5 = 0. The roots are

(-5 + sqrt(25+20))/2 and (-5 - sqrt(25+20))/2

(-5 + sqrt(45))/2 and (-5 - sqrt(45))/2

(-5 + 6.70)/2 and (-5 - 6.70)/2

(1.70)/2 and (-11.70)/2

0.85 and -5.85