Calculus

73474949444999272725678251628909813.345267777777776663

Yes.

y = kn / (1 + n2)

First, let's express it with negative exponents:
y = kn * (1 + n2)-1

Then apply the chain rule:
dy|dn = k(1 + n2)-1 - kn(1 + n2)-2 * 2n

And simplify:
dy|dn = k / (1 + n2) - 2n / kn(1 + n2)

2250000000

x = (y-b)/m

Get x on it's own so 8x = x -4 would become

7x = -4

x = -0.57

I see something like this and I use the quadratic formula, which solves all quadratic equations. Discriminant, by inspection, looks good for two real roots.

X = -b +/- sqrt(b^2 - 4ac)/2a

a = -3

b = -1

c = 2

X = -(-1) +/- sqrt[(-1)^2 - 4(-3)(2)]/2(-3)

X = 1 +/- sqrt(25)/-6

X = {1 +/- 5}/-6

X = -1

X = 2/3

My TI-84 confirms these values for X

If 6 +2=8 then 8 =6+2

I think...

but then it could also be 4+4 =8

hope I helped :)

y = 12x + 5x - 7

Since '12x' and '5x' both have the same variable, you are able to combine them. To do this you just need to add 12 + 5 to get 17.

After doing this you can rewrite the equation as y = 17x - 7.

You can then solve this equation for different values by plugging in a number for 'x' or 'y' or graphing the equation.

It could resemble a pie with roughly 1/4 of it missing.

To solve a quadratic equation (which means to find the zeros of that equation) you have two options

1. type the equation into a graphing calculator and graph the resulting equation and find where the x intercepts are (where y=0)

2. solve the quadratic equation by factoring

First, set the equation equal to zero.

x2-8x-9=0

Then find the resulting x values by "smiling"

multiply the first term and the last term (x2) (9)

find two numbers that add to -8 and multiply to -9

these two numbers are -9 and 1

x2- 9x 1x-9

x(x-9) 1(x-9)

the resulting factors are 0= (x+1)(x-9)

to find the roots, set these factors = 0

x+1=0

x=-1

x-9=0

x=9

Therefore, the solutions for the quadratic equation are x=-1 and x=9

x2+12x+5 = 3

x2+12x+5-3 = 0

x2+12x+2 = 0

3x + 2x = 5x

logbase5 of x =z

x=5^z

It can be considered a philosophical question, without any real answer.

But the easiest answer to this question is to consider the fact that an infinity is an infinity and have a beginning but no end. Then every infinity would have beginnings but no ends, so no matter how many you have, every infinity would still be equal to oneanother.

i know you add x to x and y to y but not x to y or y to x

so i answer the exponents and get 334y over 225y times 13824x

324y

----------------

225y 13824x

so i think that you would have to divide 324y by 225y and get 1.44

so if i am right you get

1.44 y 13824 x

They add up to: 8x2

An equation.

5x + 2 = x + 12

5x - x = 12 - 2

4x = 10

x = 10/4

x = 5/2 or 2.5

When x = -2 then y = 4 which is the common point of intersection of the two equations.

8

x² + y² - 4x + y - 1 = 0

( x² - 4x ) + ( y² + y ) = 1

( x² - 4x + 4 ) + [ y² + y + (1/4) ] = 1 + 4 + (1/4)

( x - 2 )² + [ y + (1/2) ]² = [ √(21) / 2 ]²

This equation represents a Circle with

Centre ≡ ( 2, -1/2 ) and Radius = √(21) / 2.

________________________________________

Happy To Help !

________________________________________

Piece wise functions can do everything. Take two pieces of two rational functions, one have a horizontal asymptote as x goes to -infinity and the other have a slanted (oblique) one as x goes to +infinity.

It is still a rational function.