Formula for volume of a trapezoidal prism?
the volume of a trapezoidal prism is equal to the height times the base area of the trapezoid.
First you find the area of trapezoid h(a+b)/2
h is the height of the trapezoid, not the height of the prism
a is the length of the top
b is the length of the bottom
Then you find the volume of the trapezoidal prism with this formula H*h(a+b)/2
H is the height of the prism.
Multiply H by the area of the trapezoid that you found in step one.
How do you solve 2 z -5 equals 11?
2z - 5 = 11
Add 5 to both sides: 2z = 16
Divide both sides by 2: z = 8
How long will it take to count to 1 billion?
If you count one number per second, and never stop to sleep or eat or anything, it will take over 31 years.
The taper angle is the angle where a thread is tapered as it is created. The formula to find it is to subtract the small diameter from the large diameter and multiply by 28, then divide by the length of the taper.
What is the answer of y equals 9x plus 3?
Every different possible value for 'x' gives a different value for 'y'. There are
an infinite number of pairs like that, and every one of them is an "answer".
Here are a few:
X . . . . Y
-3 . . . -24
-2 . . . -15
-1 . . . -6
0 . . . . 3
1 . . . . 12
2 . . . . 21
3 . . . . 30
4 . . . . 39
5 . . . . 48
How do you solve 1 minus cosx divided by sinx plus sinx divided by 1 minus cosx to get 2cscx?
(1-cosx)/sinx + sinx/(1- cosx)
= [(1 - cosx)*(1 - cosx) + sinx*sinx]/[sinx*(1-cosx)]
= [1 - 2cosx + cos2x + sin2x]/[sinx*(1-cosx)]
= [2 - 2cosx]/[sinx*(1-cosx)]
= [2*(1-cosx)]/[sinx*(1-cosx)]
= 2/sinx
= 2cosecx
The question concerns a cubic (order 3) divided by a binomial (order 1) and so the quotient has order 3 - 1 = 2 and the remainder has order 0 (one less than the denominator).
That is
(2*x^3 + 5*x^2 - 14*x + 3)/(2*x - 3) = A*x^2 + B*x + C + D/(2*x - 3)
Multiplying both sides by 2x - 3 gives
2*x^3 + 5*x^2 - 14*x + 3 = 2A*x^3 - 3A*X^2 + 2B*x^2 - 3B*x + 2C*x - 3C + D
Compare coefficients of x^3: 2 = 2A => A = 1
Compare coefficients of x^2: 5 = -3A + 2B = -3 + 2B => 2B = 8 => B = 4
Compare coefficients of x^1: -14 = -3B + 2C = -12 + 2C => 2C = -2 => C = -1
Compare coefficients of x^0: 3 = -3C + 2D = 3 + 2D => 2D = 0 => D = 0
So, The quotient is (x^2 + 4 x - 1) and the remainder is 0.
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Alternatively you can do the long division by considering the coefficients of the largest power of x - ie dividing the largest power of x (left in the dividend) by 2x (the largest power of x in the divisor) and using that as the value to add into the quotient and to multiply the divisor by before subtracting it (as in a normal long division):
_______________ x² + _4x - 1
_______--------------------------
2x - 3 | 2x³ + 5x² - 14x + 3 ___ ← 2x³ ÷ 2x = x²; put "x²" in quotient
________ 2x³ - 3x² ______________ ←(2x - 3) × x² and subtract
________ ------------
______________ 8x² - 14x ________ ← bring down "- 14x"; 8x² ÷ 2x = 4x; put "+ 4x" in quotient
______________ 8x² - 12x ________ ← (2x - 3) × 4x and subtract
______________ ------------
____________________ -2x + 3 _____ ← bring down "+ 3"; -2x ÷ 2x = -1; put "- 1" in quotient
____________________ -2x + 3 _____ ← (2x - 3) × -1 and subtract
_____________________ ---------
__________________________ 0 _____ ← nothing to bring down, result is 0, so no remainder
(The underscores in the diagram are to help align the workings.)
→ (2x³ + 5x² - 14x + 3) ÷ (2x - 3) = x² + 4x - 1
The reading could be too high or too low.
Is 60-2x equals to 70-4x what is x?
60-2x = 70-4x
60-2x+2x = 70-4x+2x
60 = 70 +2x
60-70 = 70 + 2x - 70
-10 = 2x
x = -10/2 = -5
What value of x makes 10x equals 350 a true statement?
We want to answer the equation 10x = 350
This can be done by dividing both sides by 10. That makes the equation x = 35.
Thus the value of x that makes 10x=350 is 35.
Prove that square of 2 is irrational?
It is not possible to prove something that is not true. The square of 2 is rational, not irrational.