Calculus

Hence the reason for why it is called Vector Calculus, Vector Calc. is simply an expansion in the calculus subject are in math. It deals with Taylor's Formula (in calc 2 you learn the taylor polynomial and the taylor series), theorems from Green, Gauss, and Stokes, and much more.

x - 7y = 18 ... (A)

2x - 7y = 22 ... (B)

Equation (B) - equation (A) gives

x = 4

Substituting this value of x in equation (A) gives

4 - 7y = 18

or 7y = -14 which gives y = -2

Solution: (x, y) = (4, -2)

y = 2x

6x-y = 8

Rearrange the top equation:

-2x+y = 0

6x-y = 8

Add both equations together in order to eliminate y:

4x = 8

Divide both sides by 4 in order to find the value of x:

x = 2

Substitute the value of x into the original equations in order to find the value of y:

Therefore: x = 2 and y = 4

y = x - 3 is a linear function where for each x-value we find one and only one y-value.

-5x + 1 = -10 -5x = -11
x = 11/5 = 2 1/5

2x = -3y + 10

3y = -2x + 10

y = -(2/3)x + 10

The graph is a straight line, with [slope = -(2/3)], passing through the point [ y=10 ] on the Y-axis.

The product is positive

m=-0.2

1 kilo

You have Y and you have X. F=function. Y is already a function of X because here's another way you write Y: F(X). So instead of putting Y you out F(X) which meanf "F or X" or "function of X".

x - 5

3

mana soalannya?

v = -6

2y = 4 (divide both sides by 2 to solve)

y = 2

Put 0 in for x and solve for y to find the y intercept. Put 0 in for y and solve for x to find the x intercept.

-4(0)+3y=10

y=10/3

y intercept is (0,10/3)

-4x+3(0)=10

x=-10/4

x intercept is (-10/4,0)

115

At negative six on the x-axis, draw a vertical line. That line will be a solid line because we have that x is greater than OR EQUAL TO negative six. Then shade the right half of the graph -- which is where x has a value that is to the right (greater than) negative six

Cos times Cos

The graph of a quadratic function is y = ax + bx + c or y = a(x - h) + k, where (h, k) is the vertex.

Since x2 - 12x + 40 cannot be factored, then I will complete the square which will give me the vertex. So I will draw the parabola (which opens upward) by using the vertex and the y-intercept, (0, 40).

y = x2 - 12x + 40 add and subtract 62

y = x2 - 12x + 62 - 36 + 40

y = (x - 6)2 + 4 so the vertex is (6, 4) which shows that the parabola does not intersect the x-axis.

Since the axis of symmetry is x = 6, and the y-intercept point is (0, 40), I have another point (12, 40). I can also find other points by letting x to be 2, or 3, or 4 and finding the corresponding y-values. For example, if x = 3, then y = 13. So the point (3, 13) will give me its symmetric point (9, 13), and so on. Thus, I can use all these points to draw the parabola.

Divide both sides by two. x = 2

2x=4

2x/2=4/2 2x/2=1x=x 4/2=2

x=2

-2y = 6 so y = -3

This is a horizontal line at a height of -3 units ie 3 units below the x-axis.