To start with, it is not an equation - there is no equality sign.
You need 2 independent equations to solve when you have two unknowns, x and y.
four consecutive odd, whole numbers cannot have an average of 549. four odd numbers added together would be an even number. an even number divided by another even number (in this case, four) will only yield an even number.
How do you solve 3x2 plus 10x equals 8 by factoring?
3x² + 10x = 8 Rewrite as: 3x² + 10x - 8 = 0
The only way to get 3x² is 3x and x
(3x + -- ) (x + --)
The factors of 8 are {1 2 4 8} so the answers must be a pair of them.
With 4 factors, and a negative sign (the -8), there are only 8 ways this can be written:
(3x + 1)(x - 8) = 3x² - 23x - 8
(3x + 2)(x - 4) = 3x² -10x - 8 (almost)
(3x + 4 )(x - 2) = 3x² - 8x - 8
(3x + 8)(x - 1) = 3x² +5x - 8
(3x - 1)(x + 8) = 3x² +23x - 8
(3x - 2)(x + 4) = 3x² + 10x -8 ◄ Success!
(3x - 4)(x + 2) = 3x² +2x - 8
(3x - 8)(x + 1) = 3x² -5x - 8
Trial and error, error, error, is the key to this kind of problem. Seeing the -10x early can point you to see that maybe changing the signs can work. ■
5 to the x power times 12 to the x power equals 17 to the x power what is x?
5x 12x = 17x
x log(5) + x log(12) = x log(17)
x [ log(5) + log(12) ] = x log(17)
x log(60) = x log(17)
x = 0
This actually checks. Since anything to the zero power is ' 1 ',
50 120 = 1 times 1, or 1
and 170 = 1
Solve y equals x2-4x plus 3 and y equals x-1 algebraically?
y = x2 - 4x + 3
y = x -1
Substitute the 2nd equation into the first
x -1 = x2 -4x + 3
Rearranging:
x2 -4x -x +3 +1 = 0
x2 - 5x +4 = 0
Solving this quadratic equation in x by factorising gives 2 values for x
x1 = 4
x2 = 1
Substituting these into the original equation for y (y=x-1) gives
y1 = 3
y2 = 0
So the 2 solutions to the equations are:
x1=4
y1=3
and
x2 = 1
y2 = 0
Solve for y when 2x equals 2y plus 3?
2x = 2y + 3
So 2y = 2x - 3
and y = x - 1.5
It is not possible to solve a single linear equation in two variables, other than to express one variable in terms of the other.
since a=5 you can put that into your equation of a+7=12
a=5
a+7=12
5+7=12
12=12 Correct
So yes the given number is a solution to the given equation
What is the value of x when 2x plus 3 equals 3x - 4?
2x + 3 = 3x - 4
7 = 5x
1.2 = x
* * * * *
Not quite right, I'm afraid:
the correct answer is x = 7.
Here's one way to find it:
2x + 3 = 3x - 4.
Then,
2x + 3 - 3x + 4 = -x + 7 = 0, and
x = 7,
which is the answer we sought.
Checking, we try substituting 7 for x,
in the original equation:
Does 2x + 3 = 3x - 4, when x = 7?
Let's try:
2(7) + 3 = 17, and
3(7) - 4 = 17.
Yes, it does;
thus assuring us that our answer is correct.
X to the second power plus seven x plus twelve equals what?
There are an infinite number of different quantities to which it could be equal,
depending on what the value of 'X' happens to be at the moment.
What is x if x squared plus x equals 56?
7 or -8
72+7 = 56
(-8)2+(-8) = 56
You can solve this using some simple algebra.
Let x be the number you are looking for.
x2 +x-56-0
This can be factored as:
(x-7)(x+8)=0
Now use the zero property that says if AB=0, A=0 or B=0 (or both)
So x-7=0 and x=7 or
x+8=0 and x=-8
What is x plus nine greater than or equal to thirteen?
you have x+9>13
so subtract 9 from both sides to get your answer
What is the inverse to the statement x equals y?
x=y is the identity. It is its own inverse.
So the inverse is y=x.
How do you solve x squared minus two x plus one equals zero?
x2-2x+1 = 0
(x-1)(x-1) = 0
x = 1 and also x = 1
How it is 10 base 10 equals A base 11?
Base 10 is based on groupings of 10, and the digits are called 0, 1, 2, 3, 4, 5, 6, 7, 8, and 9. Base 11 is based on groupings of 11, and the digits are called 0, 1, 2, 3, 4, 5, 6, 7, 8, 9, and A. A is used instead of 10 to avoid confusion, because it is a single digit, not two digits that actually have the base 10 value of 11.
Notice in 10 base 10, you are using 2 digits, a 1 in the tens place and a 0 in the ones place. In base 11, you only need 1 digits, an A, which has the same effective value.
What is log w log x 3 log x as the logarithm of a single quantity?
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