Calculus

-- Find the point (x = -4) on the x-axis. (It's 4 units to the left of the origin.)

-- Draw a vertical line through that point, as far up and down as you want to go. (Technically, it never ends.)

6x + 8 = x + 6

Subtract x from each side: 5x + 8 = 6

Subtract 8 from each side: 5x = -2

Divide both sides by 5: x = -0.4

x = -0.4

It depends on their orientation - back to front (in contact), back to front with a 30 cm gap, or head to toe.

* If the line were 1 cm units the line would be 1,100,000 km long. * The in contact line would then be (at 30 cm/person) 33,000,000 km long * The 30 cm gap line 66,000,000 km * The head to to toe line (80 cm/unit) 88,000,000 km

x + 4x + 3 = 17

(Take 3 from both sides)


x + 4x = 14


= 5x = 14


(divide both sides by 5)


x = 2.8

Find x when y = 0

0 = -3x + 4 so 3x = 4 or x = 4/3

Mark the point (4/3, 0).

Find y when x = 0

y = 0 + 4 so y = 4

Mark the point (0, 4)

Join the above two points and extend the line in both directions.

3+4*8/2 = 3+4*4 = 3+16 = 19

x1:y1 = x2:y2

4:-2 = x2:5

x2 = (4*5)/-2

x2 = -10

The domain of y = x2 is [0,+infinity]

2(x - 1)(2x + y)

'y' is a variable. '15' is not.

[ y+15 ] is an expression in one variable.

Unfortunately, limitations of the browser used by Answers.com means that we cannot see most symbols. It is therefore impossible to give a proper answer to your question. Please resubmit your question spelling out the symbols as "plus", "minus", "equals", etc. There is no visible symbol between 9 and 8.

It is an equation and the value of x is 4

2 x 5 x 10 - 1= n

10 x 10 - 1=n

100 - 1 =n

99= n

The question is suppose to read:

Find the equation of the line tangent to y=(x²+3x)²(2x-2)³, when x=8

Trial and error! x cubed can be 1, 8, 27, 64 etc also -1, -8, -27, -64 ... None of these are a multiple of 10 different from 51, so there is no solution in integers...

Use the power/chain rules:

d/dx (2 cos2 x) = 2 d/dx (cos x)2 = (4 cos x)*d/dx(cos x) = -4 cos x sin x = -2 sin 2x

to factor (x2-16x+64), you need to find two number whose product is 64 and whose sum is 16.

These two numbers are 8 and 8.

(x2-16x+64)=(x-8)(x-8)

Given y = 2x + 4, plug in x = 42 and simplify:

y = 2(42) + 4

y = 84 + 4

y = 88

-3x+7y=-8 = [1] 5x-11y=[2]

5[1] gives -15x + 35y = -40

3[2] gives 15x - 33y = 48

[2] + [1] gives 2y=8 therefore y=4

5x - 11(4) = 16 therefore x = 12

please cans someone tell me what the answer is if x ='s 3 what is the answer to this - 2(x-1) i will be very greatful if you told me the answer thankyou!!

7x + 6x - 1 = 0

7x + 6x = 1

13x = 1

x = (1/13)

This is not calculus btw.

Its basic algebra.

x-2=7 x=7+2
x=9
dips**t

8x2-16x+8=8(x-1)2

How to do it:

First factor out the 8 and you have

8(x2 -2x+1)

look at the 1 and not the only two way to get 1 are by multiplying -1x-1 or 1x1

Only the -1x-1 will work and give us the -2x.

no he created the laws of force