Factoring and Multiples

Oh, dude, you're hitting me with some math now? Alright, so you're looking at the quadratic expression x^2 + 5x + 4. To factor this, you want to find two numbers that multiply to 4 (the constant term) and add up to 5 (the coefficient of the x term). Those numbers are 1 and 4, so the factored form is (x + 1)(x + 4). That's it, easy peasy lemon squeezy!

Well, honey, if a number is even, that means it's divisible by 2. So yes, all even numbers have 2 as a factor. It's like asking if water is wet - the answer is right in front of your face!

Theo says that a and b are factors of c is this correct

4 x 10000

252 is a composite number because it has factors other than 1 and itself. It is not a prime number.

The 18 factors of 252 are 1, 2, 3, 4, 6, 7, 9, 12, 14, 18, 21, 28, 36, 42, 63, 84, 126, and 252.

The factor pairs of 252 are 1 x 252, 2 x 126, 3 x 84, 4 x 63, 6 x 42, 7 x 36, 9 x 28, 12 x 21, and 14 x 18.

The proper factors of 252 are 1, 2, 3, 4, 6, 7, 9, 12, 14, 18, 21, 28, 36, 42, 63, 84, and 126 or,
if the definition you are using excludes 1, they are 2, 3, 4, 6, 7, 9, 12, 14, 18, 21, 28, 36, 42, 63, 84, and 126.

The prime factors of 252 are 2, 2, 3, 3, and 7. Note: There is repetition of these factors, so if the prime factors are being listed instead of the prime factorization, usually only the distinct prime factors are listed.

The distinct prime factors of 252 are 2, 3, and 7.

The prime factorization of 252 are 2 x 2 x 3 x 3 x 7 or, in exponential form, 22 x 32 x 7.

)the answer is the left end of the graph of the function goes up and the right goes down, 2)it has 5 zeros and at most 4 relative maximums and minimums, 3)and it is a reflection and a translation to the left of the parent function.

Numbers with exactly 6 factors are perfect squares of prime numbers. The prime factorization of a number with exactly 6 factors is in the form ( p^2 ), where ( p ) is a prime number. There are 10 prime numbers less than 30: 2, 3, 5, 7, 11, 13, 17, 19, 23, and 29. So, there are 10 numbers less than 30 that have exactly 6 factors.

The GCF of 12, 18, and 27 is 3

The factors of 12 = 1x12, 2x6, 3x4 = 1, 2, 3, 4, 6, and 12

The factors of 18 = 1x18, 2x9, 3x6 = 1, 2, 3, 6, 9, and 18

The factors of 27 = 1x27, 3x9 = 1, 3, 9, and 27

The GCF is 3.

To find two numbers with a greatest common factor (GCF) of 15 and a least common multiple (LCM) of 270, we can use the relationship between GCF, LCM, and the two numbers. The relationship is LCM(a,b) = (a * b) / GCF(a,b). Given GCF = 15 and LCM = 270, we can substitute these values into the formula to get 270 = (15 * b) / 15. Solving for b gives us b = 270 / 15 = 18. Therefore, the two numbers are 15 and 18.

To find the highest common factor (HCF) of 264 and 308, we need to determine the largest number that divides both 264 and 308 without leaving a remainder. One way to find the HCF is to list the factors of each number and identify the highest common factor. The factors of 264 are 1, 2, 3, 4, 6, 8, 11, 12, 22, 24, 33, 44, 66, 88, 132, and 264. The factors of 308 are 1, 2, 4, 7, 11, 14, 22, 28, 44, 77, 154, and 308. The highest common factor of 264 and 308 is 44.

To find the least common multiple (LCM) of two numbers, you first need to find the prime factorization of each number. The prime factorization of 90 is 2 x 3^2 x 5, and the prime factorization of 165 is 3 x 5 x 11. Then, you take the highest power of each prime factor that appears in either factorization. Therefore, the LCM of 90 and 165 is 2 x 3^2 x 5 x 11, which equals 990.

The Highest Common Factor (HCF) of 120 and 160 is the largest positive integer that divides both 120 and 160 without leaving a remainder. To find the HCF, we need to determine the common factors of 120 and 160. The factors of 120 are 1, 2, 3, 4, 5, 6, 8, 10, 12, 15, 20, 24, 30, 40, 60, and 120. The factors of 160 are 1, 2, 4, 5, 8, 10, 16, 20, 32, 40, 80, and 160. The largest common factor between 120 and 160 is 40. Therefore, the HCF of 120 and 160 is 40.

To find the nth term of a sequence, we first need to identify the pattern. In this case, the sequence appears to be increasing by consecutive odd numbers: 2, 4, 6, 8, and so on. This means the nth term can be represented by the formula n^2 + 2. So, the nth term for this sequence is n^2 + 2.

LOWEST goes with Common Multiple (18)

Common Factor goes with HIGHEST (3)

Well, isn't that a happy little question! 170 can be divided by 1, 2, 5, 10, 17, 34, 85, and 170. Just like painting a beautiful landscape, numbers can be divided in many different ways to create something special. Just remember, there's no mistakes in math, just happy little numbers!

2 x 16

4 x 8

8 x 4

16 x 2

15 x 10 = 150

30 x 5 = 150

50 x 3 = 150

75 x 2 = 150

the common factors of 140 and 25 are 1, and 5

The GCF is 5p.

Oh, dude, it's like this - when you're dividing multiples of 10, patterns can totally make your life easier. You just look at how many zeros are in the number you're dividing by, and that tells you how many places to move the decimal point in your answer. It's like a little math hack that can save you some brain power.

Since 52 is an even number, it will divide by '2'

Hence

2)52 = 26

2)26 = 13 A prime number.

Hence the factors of '52' are

1,2,4,13,26,52.