Math and Arithmetic

C2H6 + O2 = CO2 + H2O

There are two carbons in the reactant, so there are two carbon in 'CO2', by writing '2CO2' .

Hence

C2H6 + O2 = 2CO2 + H2O

Similarly, there are six hydrogen in the reactant, so there are six hundreds in H2O , by writing ' 3H2O .

Hence

C2H6 + O2 = 2CO2 + 3H2O

To balance the oxygens, we now think ' backwards'.

We note in the products there are 2 x 2 = 4 oxygen in CO2. and 3 x 1 = 3 in H2O. So we need 4 + 3 = 7 oxygens in the reactants. We already have '2' oxygen in the reactants as 'O2' . To make this up to '7' , we write ' 3 1/2' as the molar ratio/. ( 2 x 3 1/2 = 7)

Hence C2H6 + ( 3 1/2)O2 = 2CO2 + 3H2O

Chemists do NOT like fractions in the molar ratios. So to remove the '3 1/2' we multiply the whole reaction eq'n by '2'.

Hence

2C2H6 + 7O2 = 4CO2 + 6H2O is the balanced reaction eq'n.

NB Note the number of each type of atom are equal on both sides.

4 carbons

12 hydrogens

14 oxygens.

NNB When doing these combustion eq'ns for alkanes, alkenes, alkynes, etc., Think to forward balance the carbons and hydrogens, then 'Back' think of the number of oxygens.

47 x 24

Long Multiplication

47

x 24

940 ( 20 x 47)

+188 (4 x 47 )

1128

===== The answer!!!!!

6x - 13 = 47

Add '13' to both sides

Hence

6x + 13 - 13 = 47 + 13

6x = 60

Divide both sides by '6'

6x/6 = 60 /6

Cancel down

x = 10 The answer!!!!!

To solve the equation ( (5x) - (2(x - 3)) = 0 ), first distribute the -2: ( 5x - 2x + 6 = 0 ). This simplifies to ( 3x + 6 = 0 ). Next, subtract 6 from both sides to get ( 3x = -6 ), and then divide by 3 to find ( x = -2 ).

Sexual position 71 typically refers to a specific position in the "Kama Sutra," which categorizes various sexual positions and techniques. The details of position 71 can vary, but it generally involves unique body alignments that promote intimacy and pleasure. The Kama Sutra is known for its exploration of different ways to enhance sexual experiences through creativity and connection. For specifics, it's best to consult a comprehensive guide to the Kama Sutra or similar resources.

The number 9000000000000000000000000 is called nine septillion in the short scale system, which is commonly used in English-speaking countries. In the long scale system used in some European countries, this number is called nine quadrillion. It is important to specify which numbering system is being used to accurately convey the value of such a large number.

4/5 is in its simplest form.

100

100

216

yes

174 cm is 1.74 meters.

So 1.74*1.74 = 3.0276 square meters.

A cylinder !

Thirty seven point zero two five

Decimal 37 expressed in binary form is 100101 (or 00100101).

Oh, dude, that's easy math! So, 495 divided by 45 equals... drumroll, please... 11! So, 45 can go into 495 11 times. Like, it's not rocket science, just basic division, you know?

Oh, dude, 5 meters is definitely greater than 500 centimeters. I mean, it's like comparing a tiny ant to a giant elephant. One's just way bigger than the other, you know? So yeah, 5 meters wins this size competition, hands down.

14/56

is 1/4

Method

'7' is a common factor of both numbers. So cancel down by '7'

Hence 14/56 = 2/8

'2' is a common factor of '2' and ;8;, So cancel down again.

2/8 = 1/4

The answer in simplified form !!!!!

7.14 x 10^(-5)

9 times with a remainder of 4.

It depends what you want 21 days to be a fraction of.

Most commonly, if you mean a fraction of a week:

1 week = 7 days

So:

21 days ÷ 7 days = 3 weeks

As a fraction:

21/7 = 3

So 21 days = 3 whole weeks, or 3/1 as a fraction.

If you mean a fraction of a month or year, it would be different.

it is .10 is closer, because .10 times 10=1

With .05 it would be .05 times 20=1

Correct general military aviation term for close quarter combat since they would need to visually identify the hijacked aircraft before firing. Also in reference to the short range AIM-9 sidewinder missile that would be used to bring them down.

The students in the class exhibit a wide range of ability levels, with some demonstrating advanced skills in critical thinking and problem-solving, while others may struggle with basic concepts. A few students excel in creative tasks and group discussions, showcasing strong communication skills, whereas others may require additional support to engage fully. This diversity presents opportunities for peer learning, as stronger students can help their peers, fostering a collaborative environment. Overall, the varied ability levels highlight the need for differentiated instruction to meet each student's unique learning needs.

ans is 10 marbles