Numbers

because they are just not

382930400239 − 200000000 = 382730400239

Negative number = -N , where 0 < N < ∞ .

Positive number = +K , where 0 < K < ∞ .

Two hundred forty-eight and sixty thousand, one hundred fifty-three hundred-thousandths.

Whole numbers do not contain decimals or fractions because they are integers in the form of: 0 1 2 3 4 5 6 7 .... etc

Thirty seven million, two hundred and fifty one thousand, two hundred and eighty five

For positional place value purposes as for example to distinguish the difference between 207 and 27

42 is a whole number and is already in its simplest form.

2 6/8 - 5/6 = 2 18/24 - 20/24 = 1 24/24 + 18/24 = 1 42/24 - 20/24 = 1 22/24 or 1 11/12

Because 2.02 is larger in value than 0.002

4

Three hundred seventy-two million five hundred twelve thousand eight hundred three.

this is not a question

22,000,000 = (2 x 107) + (2 x 106) + (0 x 105) + (0 x 104) + (0 x 103) + (0 x 102) + (0 x 101) + (0 x 100)

-64,588

It is: 4001

704009

It is: 183

First Answer:

With one six-sided die, the odds are one in two (right). With two dice, the odds are five in twelve (this is wrong).

Second Answer:

Broken down the following can be seen:

Number, Is odd?, Prime composition, Is prime?

1, Yes, 1^1, Yes

2, No, 2^1, Yes

3, Yes, 3^1, Yes

4, No, 2^2, No

5, Yes, 5^1, Yes

6, No, 3^1*2^1, No

Full disclosure however, the arguments that 1 and 2 are prime numbers are... well, debated. We'll just presume they are to simplify things (the arguments are rather complex compared to such a simple question; honestly though, I'm of the camp that believes 1 and 2 are not prime numbers, which makes the answer 2/6 for a single die).

So, the numbers that are both prime and odd are 1, 3, and 5. Really on a six sided dice you're just asking if what the probability that a number rolled is ODD will be. If this were a 16-sided die, the answer would simply follow the same logic, but be of a slightly different in nature.

The probability an odd number would be rolled is 1/2 for a single die (3/6). The probability that only one odd number would be rolled between two die is 1/2 * 1/2 (1/4). The probability that an odd number would be rolled but the other would be even (or visa versa) is still 1/2 * 1/2 (or 1/4). The probability that both are odd, or both are even is... again, 1/2 * 1/2 (or, again, 1/4). Lastly (and to answer your question), the probability that an odd number occurred at all when rolling two dice is the inverse of the probability that an odd number did not occur, which is 1 - (1/2 * 1/2) or 3/4, or 75%. If you think about it all possible combinations have been represented here. Take any given probability conjecture such as the probability that the first is odd and the second is even, because both possibilities are independently 1/2, the complement is likewise 1/2 and it makes life very, very simple when computing this.

sometimes, but no

No, it is not.

2 3 5 7 11 13 17 19 23 29 31 37 41 43 47 53 59 61 67 71 73 79 83 89 97

Seventy-six thousand, two hundred thirty-nine.