Oxidation Numbers

The oxidation number of Cs (Cesium) is +1, and the oxidation number of Br (Bromine) is -1. In CsBr, Cesium donates one electron to Bromine, resulting in Cs having an oxidation number of +1 and Br having an oxidation number of -1 in the compound.

KNO3 has no oxidation number.

However, the individual atoms do each have an oxidation number.

Using oxygen as the 'yardstick' at '-2' ; NB There are exceptions this rule.

There are 3 oxygens, so the oxygen component has an oxidation of 3 x -2 = -6.

So for it to be a neutrally charge molecule the potassium and the nitrogen must sum to +6.

Since potassium only loses one electron its oxidation number is '+1'. It follows that nitrogen must be in oxidation state '+5'

Summarising;-

Potassium(K) = +1

Nitrogen(N) = +5

Oxygen(O) = 3 x -2 = -6

+1+5-6 = 0

NB Nitrogen , like sulphur and phosphorus exhibit various oxidation states.

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The oxidation number of oxygen is typically -2, so for the whole MoO4^2- ion (which has a charge of -2), the total oxidation number must sum up to -2. This means that the oxidation number of molybdenum (Mo) in MoO4^2- would be +6.

The oxidation number of oxygen in oxyanions such as this is usually considered to be -2.

The oxidation state of phosphorus in the phosphate ion (PO43-) is +5. This is because each oxygen atom has an oxidation state of -2, and the overall charge of the ion is -3, so the phosphorus must have an oxidation state of +5 to balance the charges.

The oxidation number of Na in Na2CrO4 is +1 and the oxidation number of O in Na2CrO4 is -2. To find the oxidation number of Cr, we let x be the oxidation number: 2(+1) + x + 4(-2) = 0 x = +6

Therefore, the oxidation number of Cr in Na2CrO4 is +6.

Oxidation can increase resistance by forming an insulating layer on the surface of a material, hindering the flow of electrons through the material. This insulating layer can decrease the conductivity of the material and lead to an increase in resistance.

In CrO4^2-, the oxidation number for Cr (chromium) is +6 and for O (oxygen) is -2. The overall charge of the ion is -2, so the sum of the oxidation numbers must equal -2.

The oxidation number of oxygen is typically -2, and the oxidation number of fluorine is -1. Since the overall molecule NO2F has a neutral charge, we can set up the equation x + 2(-2) + (-1) = 0 to solve for the oxidation number of nitrogen. This gives us x = +4, indicating that the oxidation number of nitrogen in NO2F is +4.

+6 for Cr

The oxidation number of Hg in Hg2Cl2 is +1. This is because each Chlorine atom in Hg2Cl2 has an oxidation number of -1 and the overall molecule is neutral. Thus, the oxidation number of Hg can be calculated as follows: 2x + 2(-1) = 0, which gives x = +1.

it is +2 it is also done by causing rust

The oxidation number of Ba in Ba²⁺ is +2. This is because in ionic compounds, like BaCl₂ where Ba²⁺ is formed, the atom loses electrons to achieve a stable electron configuration, resulting in a positive oxidation state.

The oxidation number of Ag in Ag(CN)2- is +1. This is because the overall charge of the complex ion is -1, and each cyanide ion (CN-) has a charge of -1. Since there are two cyanide ions, the total negative charge is -2, leaving the silver ion with a +1 oxidation state to balance the charge.

With a few exceptions that do not apply to this formula, oxygen is always assigned a formal oxidation number of -2 per atom, and hydrogen is assigned +1 per atom. The compound as a whole must always be electrically neutral. Therefore, in this molecule, the oxidation number of the single sulfur atom must be -[-2(4) +2] or +6.

The oxidation number of lead in PbCl2 is +2. This is because chlorine typically has an oxidation number of -1, and since the compound is neutral, the oxidation numbers must add up to zero.

In the compound Fe2O3, iron has an oxidation number of +3 because oxygen typically has an oxidation number of -2. Iron needs two atoms of oxygen to balance its +6 oxidation state, hence the compound with the formula Fe2O3.

In the compound Al2O3 oxygen is oxidized to minus 2. You will note that two aluminum times plus 3 is 6, and 3 oxygen times minus 2 is minus 6; thus the combination of aluminum and oxygen yields an electrically neutral molecule, since 6 - 6 = 0.

The oxidation number of Mn in MnO4- is +7. This is determined by balancing the charge of the whole ion (-1) with the charges of the oxygen atoms (-8) and solving for the oxidation number of Mn.

The oxidation number of sulfur (S) in Li2SO4 is +6. This is because lithium (Li) has an oxidation number of +1 and oxygen (O) has an oxidation number of -2, which allows us to calculate the oxidation number of sulfur.

The oxidation state of nitrogen (N) in NH4+ is -3. Nitrogen usually has a -3 oxidation state in ammonium ion (NH4+) as hydrogen is typically considered to have +1 oxidation state and there are four hydrogen atoms bonded to nitrogen in NH4+.

The oxidation state of NH3 (ammonia) is -3. Each hydrogen atom contributes a +1 oxidation state, while nitrogen has a -3 oxidation state, resulting in a neutral molecule overall.

The oxidation state of hydrogen is usually +1, except in metal hydrides where it can be -1.

-2

The oxidation number of chlorine in the compound PbCl is -1. Each chlorine atom in PbCl has an oxidation number of -1, as lead has a fixed oxidation number of +2.