Oxidation Numbers

Boron has an oxidation number of +3. It will try to lose the three valence electrons that it has, so that it is stable. Electrons are negative, and removing them would make the oxidation number positive.

The oxidation number of gallium is typically +3. This is because gallium belongs to Group 13 of the periodic table, and elements in this group typically exhibit an oxidation state of +3 in their compounds.

The oxidation number of glycerol is 0, as it is a neutral molecule with no charge.

Oxidation state of O is -2.Oxidation state of S is +4.

The sum of the oxidation numbers of all the atoms in the peroxydisulfate ion (S2O82-) is equal to the overall charge of the ion, which is -2. Since each oxygen atom has an oxidation number of -2, and there are 8 oxygen atoms, the total contribution from oxygen is -16. This means that the sum of the oxidation numbers of the sulfur atoms must be +14 in order to balance the charge.

It depends on the compound.

+1 and +2 are the more common ones (as in Cu2I2 and CuI2 respectively).

In elemental form, its oxidation number is zero.

The oxidation numbers of each element in HNO3 are: H is +1, N is +5, and O is -2. The sum of the oxidation numbers in a neutral compound like HNO3 must equal zero.

-3

It depends on the compound. Lead can have an oxidation state of either 2+ or 4+

Germanium has 32 electrons.

They are arranged in 4 shells ; 2,8,18,4.

The inner most shell contains 2 electrons and the outermost shell contains 4 electrons.

The element Germanium is in Group 4 (Carbon group)

It is in Period 4.

Its electron configuration is ; [Ar] 3d(10), 4s(2) , 4p(2)

The [Ar] may be replaced by the FULL electrons configuration.

1s2, 2s2, 2p6, 3s2, 3p6, 3d10, 4s2,4p2.

Hope that helps!!!!!

Astatine has a valency of 1, because it is in group 7 and is part of the halogens. They say the group number is the number of valence, but the valency can't be 7. So they do 8 (the number of total outer shells allowed) - the group number if it's above 4.

8 - 7 = 1.

And all the other halogens, in group 7 like fluorine, chlorine, bromine and iodine have a valence of 1.

All in all, Astatine has a valency of 1.

Nitrogen has an oxidation number of -3. Since it is in group 15, it has 5 valence electrons. It wants to have eight, so it will gain three electrons. Electrons are negative, that's why the oxidation number is negative.

N has an oxidation state of -2

Since H is +1 for each atom (+1)(4atoms) =+4 total

The compound must be neutral

so N is -2 for each atom (-2)(2atoms)= -4 total

the orders the N and H are in does not affect the sign.

The oxidation number of the element potassium (K) is +1. This is because alkali metals like potassium typically lose one electron to achieve a stable electron configuration.

The oxidation numbers of atomic magnesium and atomic chlorine are 0. They react with each other to form magnesium chloride. After the formation of the salt, magnesium ions have +2 oxidation number where that of chloride ions is -1.

First, determine which family it is in on the periodic table. The group number equals the number of valence electrons that it has. It needs to end up with eight valence electrons to have a full octet. So if it has seven valence electrons, it will gain one electron to be stable. On the other end of the table, it will lose electrons to be stable.

Elemental Cl has zero O.number . In compounds it depend upon charge of ion

Atomic chlorine has 0 as oxidation number. The oxidation state of chlorine ion, which is made with metals is -1. When forming oxychloride anions, the oxidation state of chlorine may change from 0 to +7.

The oxidation number for 'O2' is zero(0).

However, when calculating oxidation numbers in compounds containing oxygen, then the oxygen is used as a standard at '-2'.

So as an example using potassium permanganate (KMnO4), what is the oxidation number of manganese (Mn).

In solution this dissolves producing the permanganate ion (MnO4^(-).

Note the charge on the ion is '-1'.

Since there are 4 oxygens present , then the oxidation of the oxygen moiety is 4 X -2 = -8 .

So creating a little sum

Mn + -8(oxygen moiety) = -1 (overall charge on the ion).

Mn + -8 = -1

Add '8' to both sides

Mn = (+)7 is the oxidation number of manganese.

So the formula could be written as KMn(VII)O4 . (Note the Roman numerals for oxidation number).

+1 for Na

+5 for N

-2 for each O

The oxidation number for argon is 0. All of the noble gases are inert.

The first step is to ignore potassium altogether and isolate the phosphate anion.

Phosphate has a total charge of -3. Assume that the oxygens each have an oxidation number of -2. Add those up to get -8. Then subtract (-8) - (-3) = +5.


So phosphorous has an oxidation state of +5.


This process will work for all oxygen containing anions except peroxide and superoxide.

The most common oxidation number for nickel is +2. Nickel is a transition metal that can also exhibit oxidation states of +1, +3, and +4, but the +2 oxidation state is the most stable and commonly observed.

Yes, you can get a personal D-U-N-S number, but it's usually associated with a business entity. If you don't have a business, you can still apply for a D-U-N-S number as a sole proprietor or self-employed individual.