Oxidation Numbers

The oxidation number of N in NH2OH is -1. This is because each hydrogen atom has an oxidation number of +1, and oxygen usually has an oxidation number of -2. Since the overall molecule has a neutral charge, nitrogen must have an oxidation number of -1 to balance out the charges.

The oxidation number of iodine in Ca(IO)2 is +5. This is because the overall charge of the compound Ca(IO)2 is 0, and each oxygen atom has a charge of -2, so iodine must have a charge of +5 to balance the charges in the compound.

In (NH4)2Ce(SO4)3, the oxidation number of Ce is +3. The oxidation number of ammonium (NH4) is +1, and the oxidation number of sulfate (SO4) is -2.

The oxidation number for zinc (Zn) in ZnO is +2. This is because oxygen typically has an oxidation number of -2 and the overall compound is neutral, so the oxidation number of zinc must be +2 to balance it out.

The oxidation state of nitrogen in NH4+ is -3.

The oxidation number for HCOO- is -1. This is because in the HCOO- ion, the total charge is -1 and each hydrogen atom has an oxidation number of +1, while the carbon atom has an oxidation number of +2 and the oxygen atoms each have an oxidation number of -2.

To find the oxidation number of copper (Cu) in CuO, consider that oxygen (O) usually has an oxidation number of -2. Since CuO is a neutral compound, the oxidation number of Cu can be calculated by setting up an equation where the sum of the oxidation numbers equals zero. In this case, the oxidation number of Cu in CuO is +2.

The oxidation number for Sulfur (S) in CaSO3 is +4. This is because Calcium (Ca) has an oxidation number of +2 and Oxygen always has an oxidation number of -2. By setting up the equation Ca(+2) + S(x) + 3O(-2) = 0, we find that x = +4 for Sulfur.

The oxidation number of iodine in the iodate ion (IO3-) is +5. Each oxygen atom has an oxidation number of -2, giving a total of -6 for the three oxygen atoms. To neutralize the charge of -1 on the ion, the oxidation number of iodine must be +5.

The oxidation number for CO3 with a charge of -2 is 2.

CH3CHOHCH2CH3 undergoes oxidation to form CH3COCH2CH3 (acetone). The alcohol group in the original molecule is converted into a ketone group during oxidation.

Metals, such as iron and copper, are most likely to experience oxidation. Other materials like certain plastics and organic compounds can also undergo oxidation depending on their chemical structure and exposure to oxidizing agents.

In NaBrO2, the oxidation numbers are as follows: Na is +1, Br is +5, O is -2.

The oxidation number of oxygen (O) in the compound H2O (water) is -2. Hydrogen typically has an oxidation number of +1 in compounds, so the two hydrogen atoms in water have a combined oxidation number of +2. Since the overall charge of the compound is neutral, the oxidation number of oxygen must be -2 to balance out the charge.

The oxidation number of Bi in Bi(OH)3 is +3. Oxygen generally has an oxidation number of -2, and since there are three hydroxide (OH-) ions, each with a -1 charge, the oxidation number of Bi can be calculated as follows: x + 3(-2) + 3(-1) = 0. Solve for x to get x = +3.

Any balanced equation for a chemical element; the chemical symbol of chromium is Cr.

The oxidation number of an element in a compound is determined by how many electrons it gains or loses to achieve stability through a full valence shell. Stability can be achieved by reaching a noble gas configuration, where the element has a complete outer shell of electrons. This often corresponds to a specific oxidation state for the element in the compound.

Yes, some metals can exhibit multiple oxidation numbers due to the ability to lose electrons from different orbitals. These variable oxidation states arise from the different ways in which the electrons in the outermost energy levels can be lost.

The oxidation number of Br in BrF is +1. Fluorine always has an oxidation number of -1 in compounds. Therefore, since the overall charge of the BrF molecule is 0, the oxidation number of Br must be +1 to balance out the -1 from fluorine.

The oxidation number of Fe in Fe(CN)6 is +2. Each CN group has a charge of -1, and since there are a total of 6 CN groups surrounding Fe, they contribute a total charge of -6. Therefore, the oxidation number of Fe must be +2 to balance the charges.

If Br had an oxidation number of +7, the net charge on the ion would be +1, and not -1. Thus, the oxidation number for Br in BrO3- should be 5+.

The oxidation number for Cl in KClO3 is +5. This is because oxygen has an oxidation number of -2 and potassium has an oxidation number of +1, so the total oxidation numbers must add up to zero for the compound.

The oxidation number of phosphorus in the PO3-4 ion is +5. Each oxygen atom has an oxidation number of -2, so the total negative charge from the oxygen atoms (-2 x 4 = -8) must be balanced by the positive oxidation number of phosphorus to give an overall charge of -3 for the ion.

The oxidation number of iron in ferric oxide (Fe2O3) is +3. This is because oxygen typically has an oxidation number of -2, and since there are 3 oxygen atoms in Fe2O3, the total oxidation number from oxygen is -6. In order for the compound to be neutral, the oxidation number of iron must be +3 to balance out the -6 from the oxygen atoms.