Probability

There are 10560 possible committees.

The probability of drawing aces on the first three draws is approx 0.0001810

If you throw a single fair coin multiple times, the probability of getting NO head is:For 1 throw: 1/2

For 2 throws: 1/2 squared = 1/4

For 3 throws: 1/2 cubed = 1/8

etc.

The probability of getting AT LEAST ONE head is the complement; for example, for 3 throws, it would be 1 minus 1/8.

That would depend on how many numbers are on the spinner and the cube. The more numbers there are, the less likely it is that they would both land an any given number.

From a scale of 1 to 0 probability measure an event will happen, maybe it will happen or it will not happen.

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If 4 are available, there are 24 possible ways to assign them. If 7 then there are 840.

It is 1/8.

It is 11/18.

The answer depends on what the distribution is!

If you throw the fair die once then the chances are two as there are two numbers to be shown that is 3 or 5.

Total number of faces and numbers in dice = 6.

So, Probability of two numbers falling = 2/6 = 1/3.

If you roll the same die 180 times then chances of landing on either 3 or 5 = 180 x 1/3 = 60.

Well, in a deck of cards, there's 2, 4, 6, 8, and 10, so that's five cards. Take those five cards and multiply it by four, because there's four different suits (clubs, diamonds, spades, and hearts.) This gives you 20, out of 52 cards, or a 20/52 chance. You can reduce this by dividing by 4, to get a 4/13 chance. You can use a calculator to divide that out and find the percentage answer, which is 38.5 percent.

If you include the two jokers, then you have a 20/54 chance of drawing an even number, which works out to a 37 percent chance.

It is 0.8

It is a discrete random variable.

It is the outcome space.

one in three

1 2 = under 3

3 4 5 6 = at least 3

so 4/6 probability

coin is 1 in 2

4/6 x 1/2 = 4/12 = 1/3

Pr(Both picked 3) = 1/16Pr(Both picked the same) = 1/4.

Assuming a normal distribution 68 % of the data samples will be with 1 standard deviation of the mean.

It is 1/7 if a ball is selected at random.

Risk

It is true.

Assuming a normal distribution:

If 16% are less than 307, then 84% are greater than 307.

Using single tailed normal tables we want the z value which gives 84%-50% = 34% = 0.34 to the left of the mean; this is z ≈ -0.995

z = (value - mean)/standard deviation

→ standard deviation = (value - mean)/z ≈ (307 - 312)/-0.995 ≈ 5.03

The z value of 322 is z ≈ (322 - 312)/5.03 ≈ 1.99

Using the single tailed tables give the value of the normal distribution for z = 1.99 as approx 0.477 to the right of the mean.

This means that 0.477 + 0.5 = 0.977 are less than 322

→ 1 - 0.977 = 0.023 = 2.3 % are greater than 322

→ probability greater than 322 is 2.3%

It is 0.000181, approx.

One. There is one card for each combination of number and suite.