Probability

The probability of getting zero tails is 1/2. The probability of getting zero tails twice in a row is 1/2 x 1/2 = 1/4. The probability of getting zero tails three times in a row is 1/2 x 1/2 x 1/2 = 1/8, etc... .

The probability is 1/4

0.5

If the underlying distribution of the product is normally distributed then (and only then) the normal distribution can be used to identify specimens that are outside the acceptable range.

There are 12.

You calculate the standard error using the data.

either 4 in 52 chances or 1 in 13 chances.

If only two cards are drawn from a standard deck of cards, with the first card replaced before drawing the second, the answer is 0.005917 (approx). If the first card is not replaced, the probability increases to 0.006033.

CHEESE

cheese has 6 letters in it. if you have a word with different letters, you do the factorial of the number of letters there are. but you can not do that in this word. since it has 3 E's, then you mut do 6!(factorial) divided by 3! then the answer would be 120

The answer depends on drawing a 9 from WHAT!

yes it is true

An event will happen or not so its probabilty is between 0 (never happen) and 1 (will surely happen).

The probability is a measure of its chance to happen.

A negative probability would have no sense.

You can think about probabilty this way: imagine a 1-litre bottle, it can be empty (0 litre) or full (1 litre) and any value between 0 and 1 but the value can't be negative.

It does not, so the question is based on a misunderstanding of probability.

Well, there are 9 letters in Tennessee, and, based on the question, you can only use each letter once.

The first letter has 9 possible outcomes.

The second letter only has 8, because you have already used one.

The third would have 7, etc.

9 * 8 * 7 * 6 * 5 * 4 * 3 * 2 * 1 = 322,880

No, not if it is a fair coin.

There is not enough information to answer your question. To determine a Z-Score, the mean and standard deviation are also required.

4

If the marbles are all red - 100%. You need to give the number of each different colored marble

Yes.

I'm assuming this is a combinations problem.

nCk = n!/(k!(n-k)!) is the general equation.

In your case n= 11 and k = 5

for 11!/(5!(11-5)!) = 11!/(5!*6!) = (11*10*9*8*7)/(5*4*3*2*1) = 462

The probability of an even must be a real number in the range [0, 1]. 120% is outside that range.

Two events are equally unlikely if the probability that they do not happen is the same for each event. And, since the probability of an event happening and not happening must add to 1, equally unlikely events are also equally likely,

P(Winning) = 50/700 = 0.0714... ≈ 7.14 %

That depends on the rules that define the random variable.

The answer depends on the rate at which calls arrive and this is not given in the question. It also depends on the assumptions made about the type of distribution for the call rates.