Trigonometry

3x+2 x is a variable. A variable is a symbol (x, y, etc...) that does not have an assigned value.

1/2*base of triangle*height(the perpendicular)=Area of right angled triangle

Smooth

of what?

(x^2 - 25)/(x + 5)

= [(x - 5)(x + 5)]/(x + 5)

= x - 5

A pentagon has 5 sides. The perimeter is 60 so each of its sides is 60/5=12.

Area = n (s/2)^2 / tan( π /n)

= 5(12/2)^2 / tan ( π /5)

= 247.7487

Let a, b, and c be the width, height, and diagonal of the rectangle.

Pythagorus' theorem applies to the rectangle as follows: a^2 + b^2 = c^2

substitute for 'a' from Pythagoruss theroem: a = sqrt(c^2 - b^2)

Therefore, Area = a * b = b * sqrt(c^2 - b^2) <-- we don't have enough information to solve for Area (we don't know either a or b).

csc(x) = 1/sin(x) = +/- 1/sqrt(1-cos^2(x))

All triangles have angles that total 180degrees. If given 2 angles add them together and subtract (or take away from) 180, answer is angle.

Example A triangle has 2 angles of 90 & 30 degrees what is the 3rd angle. 90+30=120, 180-120=60degrees

29 seconds ago. Exactly. And dude, work on your spelling!

The area is 12889 sq metres, approx.

Trigonometry is useful in buliding, amongst other professions and industries. Trigonometry is a branch of mathematics that deals with triangles, specifically right-angled triangles. It can be used to measure the angles of a triangle as well as all three sides, as long as two measurements are given.

4

1. Use the coordinates of the vertices to establish which two sides are parallel.
2. Find the lengths of the two parallel sides (X and Y).
3. Find the equation of a perpendicular to one of these lines at a point P.
4. Find the point where this perpendicular line meets the other parallel line (Q).
5. Find the distance PQ = H.
6. Area = 1/2*(X + Y)*H

Yes

If I have this correct you are asking x^2 + 10^2 = 12^2 Then x=6.633249507108

Just add together the 4 sides

sin 300 = -sin 60 = -sqrt(3)/2 you can get this because using the unit circle.

Angles are measured by degrees. Fractions of degrees are measured in minutes and seconds.

Because it is not always convenient to convert to convert sin to cos when working with adjacent sides.

The Cartesian system allows you to describe a geometric shape in algebraic terms. This allows algebraic techniques, such as differentiation or integration to be applied to solve problems in geometry. Conversely, geometrical results can be used to solve problems in algebra.

An oxagon is not a geometric shape and so does not look like anything.

Same as a rectangle. It is, after all, a type of rectangle (lenght >< width)

To find the sin/cos at a given point on the unit circle, draw a radius to that point. Then break the radius into components - one completely horizontal and one completely vertical. The sine is the vertical component, the cosine is the horizontal component.

If you are refering to the double-angle formula for sin(x), the best way is to use what is known as Euler's identity. Euler's identity is eix = cos(x) + i*sin(x) where x is any real angle in radians, e is Euler's constant 2.71828182845... and i is the imaginary number: SQRT(-1). Assuming that is true, then ei(2x) = cos(2x) + i*sin(2x) and that is the same as saying (eix)2= cos(2x) + i*sin(2x) and substituting from the original equation: (cos(x) + i*sin(x))2 = cos(2x) + i*sin(2x). By distribution, remembering that i2 = -1, we get cos2(x) + i*2*sin(x)*cos(x) - sin2(x) = cos(2x) + i*sin(2x). Now we can separate the equation into its real and imaginary parts. cos2(x) - sin2(x) = cos(2x) and i*2*sin(x)*cos(x) = i*sin(2x), and after i cancels, there's our good old double angle formula.

If derive refers to derivative, then use the chain rule. d(sin(2x))/dx=2cos(2x)