Trigonometry

Every triangle have 6 main parts: 3 sides and 3 angles. On a right triangle one of the angles has to be a right angle, meaning it has a 90 degree angle.

Put the percent in decimal form, than mutiply it by 360 degrees.

the person who did this was ben Franklin

I am trying to find the answers to this....and no the answer is not ben Franklin...sorry

I agree it is not ben Franklin...good try though

it doesnt.

Placing a question mark at the end of a phrase does not make it a sensible question. Try to use a whole sentence to describe what it is that you want answered.

Quadrant I.

'Theta' is the eighth character in the Greek alphabet. It is not often used as a mathematical constant (such as 'Pi'), but rather as a variable. It is commonly, but not always, used to represent some arbitrary angle.

1/2 x length x width x height

They mean that the expression to the left of the sign is greater than or less than (as appropriate) the expression to the right of the sign.

It is a measure of an area, approximately equal to 492 sq metres.

We stat with the law of cosines, which we can assume to be true:

* c2 = a2 + b2 - 2ab*cos(C) Then rearrange it:

* cos(C) = a2 + b2 - c2/2ab Use the identity sin(x)=SQRT(1-cos(x))

* sin(C) = SQRT( 1 - (a2 + b2 - c2/2ab)2) Use the operator A = 1/2ab*sin(C) where A is area. Also, set one equal to 4a2b2 and factor it out.

* 2A/ab = SQRT(4a2b2 - (a2 + b2 - c2)2)/2ab ab's cancel, and the term inside the square root is the difference of two squares.

* A = 1/4*SQRT((2ab - (a2 + b2 - c2))(2ab + (a2 + b2 - c2))) when the two groups are simplified, the can be factored in binomial squares.

* A = 1/4*SQRT((c2 - (a - b)2)((a + b)2 - c2) Once again, we have differences of squares.

* A = 1/4*SQRT((c - (a - b))(c + (a - b))((a + b) - c)((a + b + c)) Simplify.

* A = 1/4*SQRT((c + b - a)(c + a - b)(a + b - c)(a + b +c)) Here comes the tricky part. We have four parts here. Three have two terms positive and one negative. Having a + b + c is like having the P. If we have a + b - c, that is like saying P - 2c, right? So to make it even easier, we can call s, the semi-perimeter, P/2. Then we can say a + b - c is 2s - 2c, or 2(s - c). We can apply that to all parts except the last one, which is just 2s.

* A = 1/4*SQRT(2(s - a)*2(s - b)*2(s - c)*2s) The two's can multiply together to 16 and come out of the root, canceling with the 1/4. we are left with good old Heron's formula.

* A = SQRT(s(s - a)(s - b)(s - c))

It's possible that either the angles or sides are labeled according to length or size.

Assume the angle u takes place in Quadrant IV.

Let u = arctan(-12). Then, tan(u) = -12.

By the Pythagorean identity, we obtain:

sec(u) = √(1 + tan²(u))

= √(1 + (-12)²)

= √145

Since secant is the inverse of cosine, we have:

cos(u) = 1/√145

Therefore:

sin(u) = -√(1 - cos²(u))

= -√(1 - 1/145)

= -12/√145

Otherwise, if the angle takes place in Quadrant II, then sin(u) = 12/√145

That depends on your profession. If you are a math teacher, then you might use a lot of Trig. If you are an engineer, working with forces on any object from different directions, then you would use trig. Electrical engineers use trig. Surveyors use trig.

Surveying the land. Laying out the position of the foundation of the building.

The double angle formula states that sin(2x) = 2sin(x)cos(x), and because sin2(x) + cos2(x) = 1, sin(2x) = 2sin(x)*SQRT(1-sin2(x)). However, that will only give you the correct result when cos(x) is positive. (because SQRT only returns the positive square root)

If, by trigonometry theorem you mean the "fundamental theorem of trigonometry," sin2(x) + cos2(x) = 1, it is actually the Pythagorean Theorem. if you have a right triangle with a hypotenuse of one, sin(x) is one leg, and cos(x) is the other. The Pythagorean Theorem states that a2 + b2 = c2 and therefore sin2(x) + cos2(x) = 1.

There is a trigonometric identity that states that sec2(x) - tan2(x) = 1, for every x. By rearranging this formula we can find that sec2(x) - 1 = tan2(x).

Since there are 2 Pi radians in one complete turn, then the minute hand turns 1.75 * 2 Pi radians in 1.75 hours.

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If x2 + y2 = 1, then the point (x,y) is a point on the unit circle.

A Quadrantal angle is an angle that is not in Quadrant I. Consider angle 120. You want to find cos(120) . 120 lies in quadrant II. Also, 120=180-60. So, it is enough to find cos(60) and put the proper sign. cos(60)=1/2. Cosine is negative in quadrant II, Therefore, cos(120) = -1/2.

It is 3 minus 2i

Cosine squared theta = 1 + Sine squared theta

If sin θ = tan θ, that means cos θ is 1 (since tan θ = (sin θ)/(cos θ))

(Usually in and equation a/b=a, b doesn't have to be 1 when a is 0, but cos θ = 1 if and only if sin θ = 0)

The angles that satisfy cos θ = 1 is 2n(pi) (or 360n in degrees)

When n is an integer.

But if sin θ = tan θ = θ, the only answer is θ = 0.

Because sin 0 is 0 and cos 0 is 1 and tan 0 is 0

The only answer would be when θ = 0.