Trigonometry

False

1 minute of arc is one sixtieth, or about 0.01667, of a degree. The sine of of 0.01667 degrees is about 0.0002909.

Trigonometry focuses specifically on the study of triangles, and concepts that are closely related to properties of triangles. Pre-Calculus is generally a preperation for the concepts of Calculus, and often reviews or builds upon concepts learned in previous forms of mathematics, which may include information learned from Trigonometry.

first divide each side by 2 so you get...

sine^2(X)=1/2

Then make sine ^2(X)=sine(x^2)

SO you get... sine(X^2)=1/2

Then take the sine^-1 of each side it will look like this X^2=sine^-1(1/2)

type the right side into a calc which will give you a gross decimal but it works (0.5235987756)

so now you have

X^2=0.5235987756

then take the square root of each side to make it linear and you will get X=.7236012546

and that is your answer!!!! make sure to check it on your calculator...I did and it worked

* * * * *

Not quite correct, I fear. Try this:

Let s = sin θ.

Then,

2s2 = 1;

s2 = ½; and

s = ±½√2.

Therefore,

θ = 45°, 135°, 225°, or 315°;

or, if you prefer,

θ = ¼π, ¾π, 1¼π, or 1¾π.

I dont think it has uses in daily life..its just to find the area of a triangle

Example: Express sin 120⁰ as a function of an acute angle (an angle between 0⁰ and 90⁰).

Solution:

Each angle θ whose terminal side lies in quadrant II, III, or IV has associated with it an angle called the reference angle, alpha (alpha is formed by the x-axis and the terminal side).

Since 120⁰ lies on the second quadrant, then alpha = 180⁰ - 120⁰ = 60⁰.

Since sine is positive in the second quadrant, sin 120⁰ = sin 60⁰.


Example: Express tan 320⁰ as a function of an acute angle.

Solution:

Since 320⁰ lies on the fourth quadrant, then alpha = 360⁰ - 320⁰ = 40⁰.

Since tangent is negative in the fourth quadrant, tan 320⁰ = -tan 40⁰.

cos(-100 degrees)

It is because angles are measured counter-clockwise for the horizontal x-axis.

The second quadrant.

Mechanics use trigonometry to find angles mostly used in body or chassis work.

an impossible event has a probability of 0, it will never occur

a certain event has a probability of 1, it will always occur

.999 repeating = 1
So 1.0
think of it as
7/9 = .777...
8/9 = .888...
9/9 = .999... 9/9 = 1

When placed next to any angle on a triangle, the theta symbol (θ) represents that missing angle.

Name the rectangle ABCD,letting the larger side be AB(7cm) and the smaller side be AC(5cm). Draw the two diagonals across the rectangle. Name the point of intersection of the two diagonals (which resembles an X) F. Name the midpoint between the smaller side AC, to be E.

AFC is the acute angle you are looking for, angle AFE is half of that.

So AFE is a right angled triangle and AE is equal to half of 5cm, which is 2.5; FE is equal to half of 7cm, which is 3.5.

Now, taking triangle AFE,

Tan AFE=2.5/3.5

AFE=35.537 degrees

Since the angle AFE is half of the acute angle AFC that you are looking for,

multiply AFE into two

So, 35.537*2

=71.075 degrees

=71.1 degrees (to 1 decimal place)

AFC= 71.1 (ANS)

Use Pythagoras' Theorem - the hypothenuse of a right triangle is square root of (a2 + b2)

Use Pythagoras' Theorem - the hypothenuse of a right triangle is square root of (a2 + b2)

Use Pythagoras' Theorem - the hypothenuse of a right triangle is square root of (a2 + b2)

Use Pythagoras' Theorem - the hypothenuse of a right triangle is square root of (a2 + b2)

yes

Search on Google for free IGCSE past papers maths. You will get a number of sites: pick any. You will need to specify your board (Edexcel, CIE), and possibly the specification code.

y = 2*tan(2x) is an equation in two variable. There can be no answer. While x can be made the subject of the formula, that is not an *answer*.

He is 75 feet high.

The slope of a line tells a person what the rate of change is for a certain amount of time. For instance, on a graph where distance is the X axis and time is the Y axis, the slope will tell the velocity, literally, distance/time.

Putting a question mark at the end of a phrase does not make it a sensible of even an answerable question.

Sine and cosine of real numbers? Yes, they do exist. In fact, sines and cosines of complex numbers also exist. Does that answer the question?