Trigonometry

The solution is found by applying the definition of complementary trig functions:

Cos (&Theta) = sin (90°-&Theta)

cos (62°) = sin (90°-62°)

Therefore the solution is sin 28°.

No.

Approx 3440 sq metres.

Answer your self dont know

is called its area.

The ladder forms a right angle with the building: the ground and the building forming the right angle and the ladder forming the hypotenuse. If the length of the ladder is L metres, then

sin(49) = 12/L

So L = 12/sin(49) = 15.9 = 16 metres.

It too will have a value of 5

There is no largest Pythagorean triple since there's infinite amount of them. But if you're looking for one quite big, I took a few minutes for you and wrote a program that computes them (and btw is still computing them). Right now the largest one the function returned is 77893200, 128189952, 150000048. Note that you can multiply all three with any same natural number larger than one (2,3,4,...) and you'll get a Pythagorean triple larger than mine.

This describes a right triangle. This triangle has a base (X ) of 3 ft, a opposite side ( Y) of 9 ft. So, you are looking for the hypothenuse. Use the Pythagoreum theory.

In this case. Your ladder length is called H.

H^2 = X^2 + Y^2

H = sqrt X^2 + Y^2

50.3625 in DMS form is 50.21.45

50 is the D part.

Subtract 50 to get 0.3625. Multiply by 60 to get 21.75. 21 is the M part.

Subtract 21 to get 0.75. Multiply by 60 to get 45. 45 is the S part.

The cotangent of 510 degrees is: -1.73205081

The domain of cosine is all real numbers, its range is [-1,1], and its period is 2π radians.

It is: tan(86.05)*5 = 72.411 metres to 3 decimal places

In a right triangle, its Opposite/Hypotenuse I always use: Soh (sin, opposite/hypotenuse) Cah (cosine, adjacent/hypotenuse) Toa (tangent, opposite/adjacent) Hope this helped! :)

Because if you construct a right triangle in which the acute angles are 30° and 60°,

you'll find that the side adjacent to the 60° angle is 1/2 the length of the hypotenuse,

which is how you apply the definition of the cosine.

Dependent on what side you are given you would use Sin(Θ) = Opposite/Hypotenuse just rearrange the formula to Hypotenuse = Opposite/Sin(Θ).

Or if you are given the adjacent side use Cosine(Θ)=Adjacent/Hypotenuse, then:

Hypotenuse = Adjacent/Cosine(Θ)

press 2nd then click the prb button (or angle) then click 6 :D

The origin of trigonometry in the 18th century was the trigonometric knowledge at the end of the 17th century!

It depends if 1 plus tan theta is divided or multiplied by 1 minus tan theta.

There is no way to find perimeter from a 3D figure. However, you can find the perimeter of a side of a triangular prism by using perimeter formulas for a parallelogram or triangle.

The answer depends on whether a or c is the hypotenuse: b cannot be the hypotenuse since the hypotenuse MUST be the longest side.

Suppose a is the hypotenuse.

Then a2 = b2 + c2 = 122 + 182 = 144 + 324 = 468. So a = 21.63 inches (approx).

Suppose c is the hypotenuse.

Then c2 = b2 + a2 = 182 = 122 + a2. So a2 = 180 and a = 13.42 inches (approx).

Periodically

cot(15)=1/tan(15)

Let us find tan(15)

tan(15)=tan(45-30)

tan(a-b) = (tan(a)-tan(b))/(1+tan(a)tan(b))

tan(45-30)= (tan(45)-tan(30))/(1+tan(45)tan(30))

substitute tan(45)=1 and tan(30)=1/√3 into the equation.

tan(45-30) = (1- 1/√3) / (1+1/√3)

=(√3-1)/(√3+1)

The exact value of cot(15) is the reciprocal of the above which is:

(√3+1) /(√3-1)

The values of tan are limitless (that is to say, within [-inf, inf]). However, sin and cos ratios are between -1 and 1. Think about it: sin = opposite/hypotenuse. Since hypotenuse is always larger than or equal to opposite, sin must always be less than 1. Same with cos.

cos(37 deg) = 0.7986