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What is the length of the instruction queue in 8086?
6 bytes
What is size of instruction queue of 8086?
6 bytes
How many bytes are addressable the 8086?
The 8086 can address 1,114,080 bytes. (One Mb + 64Kb - 16) That does not count I/O space, it only counts memory space.
Which instruction in 8086 microprocessor is 6 bytes long?
mov
What is the size of the interrupt vector table in the 8086-8088 microprocessor?
There are 256 different interrupt vectors in the 8086/8088. Each vector is a far CS:IP address, which is four bytes. That makes the interrupt vector table 1,024 bytes.
How many memory address does this number of address lines allow the 8086 to access directly?
The 8086/8088 has 20 address lines. It can access 220, or 1MB, or 1,048,576 bytes of memory.
How many memory addresses does this number of address lines allow the 8086 to access directly?
The 8086/8088 has 20 address lines. It can access 220, or 1MB, or 1,048,576 bytes of memory.
What is the maximum length of instruction in 8086?
In the 8086 microprocessor, the maximum length of an instruction is 6 bytes. This includes the opcode, any necessary prefixes, and operands. The architecture allows for complex addressing modes, which can contribute to the instruction length, but the limit remains at 6 bytes for any single instruction.
What is the size of the instruction queue in 8086?
In 8086 the instruction queue is 6 byte long. This is because even the longest 8086 instruction is 6 byte long. Thus it is possible to prefetch even the longest instruction in the instruction set.
How many bytes are there for jump instruction in 8085?
There are 74 instructions in the 8085 microprocessor.
What is the size of each memory segment of 8086 is?
The 8086 was only capable of addressing 1Mbyte of memory. It was divided into segments of 65536 bytes (64 KB) each meaning about 16 segments.
List the unconditional branch instructions in 8086 with examples and explain?
jmp
