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In the 8086 microprocessor, memory is organized into segments and can be accessed in bytes or words. Even-addressed bytes are accessed directly using their address, while odd-addressed bytes are accessed through a combination of the even address and a specific instruction. For example, to access an odd byte, the CPU reads the word containing that byte, performing a mask operation to isolate the desired odd byte. Since the 8086 is a 16-bit architecture, it can handle both even and odd addresses efficiently, ensuring proper alignment for data retrieval.
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How many address lines will take to address the 16kilo bytes?
16KB, or 16384 bytes, can be addressed with 14 address lines. (214 = 16384)
How many bytes of memory on a 128MB computer?
The memory is to be designed so that 16-bitdata can be accessed in one .Two 64K X 8 SRAM chips have a capacity of 128KB.
What is the memory address of the last byte of a 1GB memory?
In a 1GB memory space, the total number of bytes is (1 \times 2^{30} = 1,073,741,824) bytes. Since memory addresses typically start at 0, the memory address of the last byte would be (1,073,741,824 - 1 = 1,073,741,823). Therefore, the memory address of the last byte of a 1GB memory is 1,073,741,823.
If a memory had 16 bit address bus and a 32 bit data bus what is the largest size of the memory?
A memory with a 16 bit address bus can address 216 or 65536 distinct items. If each item is 32 bits in size, then the item is 4 bytes. The size of this memory is then 262144 bytes. (256Kb)
A computer has 64MB megabytes of memory Each word is 4 bytes How many bits are needed to address each single word in memory?
The memory address space is 64 MB, which means 226. However, each word is 4 bytes, which means that you have 224 words. This means you need log2 224 or 24 bits, to address each word.
What is the address of the last byte of RAM in the Pep8 memory?
2 bytes or 16 bits
Maximum memory address space that the processor can access directly if it is connected to a 16-bit memory?
Max. memory address space= 216 X 2 bytes = 128 Kbytes
How many no of address lines required in 64kB memory?
To calculate the number of address lines required for a 64 kB memory, first convert 64 kB into bytes: 64 kB = 64 × 1024 bytes = 65,536 bytes. The number of address lines needed can be determined using the formula (2^n = \text{total number of addresses}), where (n) is the number of address lines. Since 65,536 is (2^{16}), you need 16 address lines to address a 64 kB memory.
How many memory address does this number of address lines allow the 8086 to access directly?
The 8086/8088 has 20 address lines. It can access 220, or 1MB, or 1,048,576 bytes of memory.
Ram memory is measured in bytes how many bytes are there in 2gb of ram memory?
2147483648 bytes
How many bytes does null occupy?
In most languages with a null reference, it is simply a memory address to a zero-length memory block. So the only memory it would occupy in these cases would be enough for a memory pointer: usually around 4 bytes.
What is the What is the maximum memory address space that the processor can access directly if it is connected to a 8 bit memory considering a hypothetical microprocessor generating a 8 bit address?
microprocessor can access 2^8 points which is 256 then we have 8 bit memory = 1 bytes then 1*256 =256 bytes
