sorry
Writing a C program that uses dynamic memory allocation to sort names in ascending order is a typical computer science assignment. To write this program, you must be in UNIX.
A program which is used to count the number of numbers in an array using a 8085 microprocessor is known as a assembly language program.
To write a C++ program to display the student details using class and array of object.
in 8085 microprocessor a subroutine is a separate program written aside from main program ,this program is basically the program which requires to be executed several times in the main program. the microprocessor can call subroutine any time using CALL instruction . after the subroutine is executed the subbroutine hands over the program to main program using RET instruction.
assembly language program for sorting an array using 8086 microprocessor.
write program to concatenating two sting in 8086 assembly language
Using sorted(array,reverse=True)
Yes, but not for long term storage, only while a program is executing using its stack.
To arrange numbers in ascending order using Java, you can utilize the Scanner class to read input from the user and then sort the numbers using an array. Here's a simple example: import java.util.Arrays; import java.util.Scanner; public class AscendingOrder { public static void main(String[] args) { Scanner scanner = new Scanner(System.in); System.out.print("Enter the number of elements: "); int n = scanner.nextInt(); int[] numbers = new int[n]; System.out.println("Enter the numbers:"); for (int i = 0; i < n; i++) { numbers[i] = scanner.nextInt(); } Arrays.sort(numbers); System.out.println("Numbers in ascending order: " + Arrays.toString(numbers)); scanner.close(); } } This program collects a specified number of integers from the user, sorts them using Arrays.sort(), and then displays the sorted list.
we are using just one ic in a microprocessor
//C program for Arranging 5 Numbers in Ascending Order #include<stdio.h> #include<conio.h> void main() { int a[5],i,j,t; clrscr(); printf("Enter 5 nos.\n\n"); for (i=0;i<5;i++) scanf("%d",&a[i]); for (i=0;i<5;i++) { for(j=i+1;j<5;j++) { if(a[i]>a[j]) { t=a[i]; a[i]=a[j]; a[j]=t; } } } printf("Ascending Order is:"); for(j=0;j<5;j++) printf("\n%d",a[j]); getch(); }