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Why microcomputer system based on 8 bit microprocessor have 64K memory?
Even though the 8085 is an 8 bit microprocessor, it can address 64K memory, because it has a 16 bit address bus.
How many memory locations can be addressed by a microprocessor with 14 address lines?
2^14 memory locations. In general for n-bit address bus, its 2^n
What is the What is the maximum memory address space that the processor can access directly if it is connected to a 8 bit memory considering a hypothetical microprocessor generating a 8 bit address?
microprocessor can access 2^8 points which is 256 then we have 8 bit memory = 1 bytes then 1*256 =256 bytes
How many locations can be addressed by a microprocessor with 14 address line?
2^14 memory locations. In general for n-bit address bus, its 2^n
How many address lines are required to access 1MB RAM using microprocessor 8086?
The 8086/8088 microprocessor has a 20 bit address bus, so the number of memory locations it can address is 220 or 1,048,576.
Which microprocessor part their tempararily data stored?
Usually memory banks made up of SRAMs or DRAMs or EPROMs consist of the storage area provided on a microprocessor. For understanding how the address space of a 20 bit address line microprocessor is organised, read about address decoding for even and odd memory addressing through SRAMs and EPROMs.
How many bit data can be stored in one memory location of 8086 microprocessor?
8
Why memory is divided in even and odd banks in 8086 microprocessor?
in 8086 there is 20 bit address bus,so it can address 1,048,576 address. At each address we can store 8 bit address (1-byte)but if want to write a word(16-bit)into a memory segment to store data in byte form then we write the data in two consecutive memory address which are even(low) and odd(high) memory.
What is the maximum memory address space that the processor can access directly if it is connected to a 16 bit memory considering a hypothetical microprocessor generating a 16-bit address?
If you assume that it has a 16-bit data bus, then it would be 128k so the microprocessor can access 2^16 points, which is 64k (from it being a 16bit address) 16bits = 2 bytes (memory) so through a 16 bit memory, it can access 2*64k, which is 128k alternatively, if its 8bit memory, 8bits=1byte 1*64k = 64k I'm no expert, and i was searching for the answer myself, hope this helped
Why memory capacity of 8085 mp is 64 KB?
The memory capacity of the 8085 microprocessor is 64 kb because the address bus is 16 bits, and you can address 216, or 64kb, with a 16 bit address bus.
How is 12 bit microprocessor made?
The Intersil 6100 family consisted of a 12-bit microprocessor and a range of peripheral support and memory ICs.
What is the meaning of lhld in 8085 microprocessor?
In the 8085 microprocessor, the instruction LHLD stands for "Load H and L Direct." It is used to load the registers H and L with a 16-bit data stored at a specified memory address. The instruction takes a 16-bit address as its operand, and the content of that address and the next sequential address are loaded into the L and H registers, respectively. This operation is useful for retrieving data from memory into these registers for further processing.
