answersLogoWhite

0

The IP register contains the address of the next instruction to fetch and execute.

Normally, IP is incremented by the number of bytes in the instruction after execution of that instruction, unless a transfer of control occurs, in which case IP is loaded with a new value.

User Avatar

Wiki User

15y ago

What else can I help you with?

Related Questions

What is the function of the PC register in the 8086 CPU?

There is no PC register in the 8086/8088. It is called the IP register by Intel and it stands for the Instruction Pointer. It contains the address of the current/next instruction to be executed.


Which register stores intrrupt and subroutine return address register in 8086?

In the 8086 microprocessor, the register that stores the interrupt and subroutine return address is the Instruction Pointer (IP) register. When an interrupt occurs or a subroutine is called, the current instruction address is pushed onto the stack, allowing the processor to return to that location after the interrupt or subroutine execution is complete. The IP register works in conjunction with the Code Segment (CS) register to determine the effective address of the next instruction to execute.


What are the multipurpose registers in 8086 microprocessor?

8086 has four multipurpose registers. 1. AX (Accumulator Register) 2. BX (Base Register) 3. CX (Count Register) 4. DX (Data Register) By Aneeta Arshad


Which register can be changed directly using pop instruction in 8086?

stack segment register


How are the code segment address generated in 8086 microprocessor?

In the 8086 microprocessor, code segment addresses are generated using a segment:offset addressing scheme. The code segment (CS) register holds the starting address of the code segment, while the instruction pointer (IP) register holds the offset of the next instruction to be executed within that segment. The effective address of an instruction is calculated by adding the value in the CS register (shifted left by 4 bits) to the value in the IP register, allowing for a total addressable space of 1 MB. This segmentation allows for efficient memory management and organization of code.


What is Bios function call in 8086 microprocessor?

The BIOS function in the 8086 microprocessor is called an interrupt function. It is an interrupt function because it is not called by a function call instruction.


What is immediate addressing of register?

i.e.-->mov ax,2000h (in 8086)


What is the need of Instruction PointerIP in 8086 microprocessor?

The Instruction Pointer (IP) in an 8086 microprocessor contains the address of the next instruction to be executed. The processor uses IP to request memory data from the Bus Interface Unit, and then increments it by the size of the instruction.


What is the size of flag register?

All of the 8086/8088 registers, AX, BX, CX, DX, SP, BP, SI, DI, CS, DS, SS, ES, IP, and FLAGS, are 16 bit registers. The AX, BX, CX, and DX registers may also be viewed as 8 eight bit registers AH/AL, BH/BL, CH/CL, and DH/DL.


What is default segment register for IP?

The default segment register for the Instruction Pointer (IP) in x86 architecture is the Code Segment (CS) register. This register is used to define the segment of memory that contains the currently executing code. When a program is executed, the CPU uses the CS register in conjunction with the IP register to determine the address of the next instruction to execute.


What is physical address in 8086 microprocessor?

Physical address in the 8086/8088 is {Selected Segment Register} * 16 + {Effective Offset Address}. It is a 20-bit address .


What is inter segment branch instruction?

The intersegment branch (or far branch) in the 8086/8088 is a branch where both the Instruction Pointer (IP) and the Code Segment(CS) registers are loaded at the same time. You can branch anywhere in memory with an intersegment branch. Contrast this with an intrasegment branch (or near branch) where only the IP register is loaded. Since the CS register is not loaded, the domain of the branch is only the 64kb segment currently selected by CS.