The IP register contains the address of the next instruction to fetch and execute.
Normally, IP is incremented by the number of bytes in the instruction after execution of that instruction, unless a transfer of control occurs, in which case IP is loaded with a new value.
There is no PC register in the 8086/8088. It is called the IP register by Intel and it stands for the Instruction Pointer. It contains the address of the current/next instruction to be executed.
8086 has four multipurpose registers. 1. AX (Accumulator Register) 2. BX (Base Register) 3. CX (Count Register) 4. DX (Data Register) By Aneeta Arshad
stack segment register
The BIOS function in the 8086 microprocessor is called an interrupt function. It is an interrupt function because it is not called by a function call instruction.
i.e.-->mov ax,2000h (in 8086)
The Instruction Pointer (IP) in an 8086 microprocessor contains the address of the next instruction to be executed. The processor uses IP to request memory data from the Bus Interface Unit, and then increments it by the size of the instruction.
All of the 8086/8088 registers, AX, BX, CX, DX, SP, BP, SI, DI, CS, DS, SS, ES, IP, and FLAGS, are 16 bit registers. The AX, BX, CX, and DX registers may also be viewed as 8 eight bit registers AH/AL, BH/BL, CH/CL, and DH/DL.
Physical address in the 8086/8088 is {Selected Segment Register} * 16 + {Effective Offset Address}. It is a 20-bit address .
The intersegment branch (or far branch) in the 8086/8088 is a branch where both the Instruction Pointer (IP) and the Code Segment(CS) registers are loaded at the same time. You can branch anywhere in memory with an intersegment branch. Contrast this with an intrasegment branch (or near branch) where only the IP register is loaded. Since the CS register is not loaded, the domain of the branch is only the 64kb segment currently selected by CS.
program counter holds the address of the next instruction.
Pins 1 and 20 in the 8086 microprocessor are (both) power and signal ground (GND).
What is the need of segments in 8086 micro-processor? Explain how the address of an instruction is calculated in 8086 using segment register