The 8086 CPU has a 20-bit address space, allowing it to address a total of 1 MB (2^20 bytes) of memory. This is achieved through a segmented memory model, where memory addresses are specified using a combination of segment and offset values. The segments can start from addresses 0x0000 to 0xFFFF, enabling the CPU to access different memory segments within the overall 1 MB range.
In 8086 pipeline concept was introduced bcoz in 8086 we started using a buffer space which fetches the instruction at the same time when CPU processes
The 8086 can address 1,114,080 bytes. (One Mb + 64Kb - 16) That does not count I/O space, it only counts memory space.
There is no PC register in the 8086/8088. It is called the IP register by Intel and it stands for the Instruction Pointer. It contains the address of the current/next instruction to be executed.
In 8086 assembly language, a physical address is the actual memory address used by the CPU to access data. It is calculated by combining a segment address with an offset address. The segment address is typically stored in one of the segment registers (CS, DS, SS, or ES), and the offset is specified in the instruction. The formula for calculating the physical address is: Physical Address = (Segment Address × 16) + Offset.
Physical addressing in the 8086 microprocessor refers to the method by which the CPU accesses memory locations using a combination of segment and offset addresses. The 8086 employs a segmented memory model, where memory is divided into segments, and each segment has a base address. The physical address is calculated by shifting the segment address left by 4 bits and adding the offset address, resulting in a 20-bit physical address space that allows the processor to access up to 1 MB of memory. This system enables more efficient memory management and allows programs to use memory in a modular way.
The address bus in the 8085 is 16 bits wide.
In the 8086 microprocessor, memory is organized into segments and can be accessed in bytes or words. Even-addressed bytes are accessed directly using their address, while odd-addressed bytes are accessed through a combination of the even address and a specific instruction. For example, to access an odd byte, the CPU reads the word containing that byte, performing a mask operation to isolate the desired odd byte. Since the 8086 is a 16-bit architecture, it can handle both even and odd addresses efficiently, ensuring proper alignment for data retrieval.
You can. There are thousands of microprocessors.
Physical address in the 8086/8088 is {Selected Segment Register} * 16 + {Effective Offset Address}. It is a 20-bit address .
Yes, the data bus and address bus play crucial roles in determining the address space of a CPU. The address bus defines the range of memory addresses that the CPU can access, with its width (number of lines) directly influencing the maximum addressable memory. The data bus, on the other hand, determines how much data can be transferred simultaneously between the CPU and memory. Together, they define the overall capability of the CPU to communicate with memory and peripherals.
The 8086/8088 has an internal 20-bit address bus and 16-bit data bus. Externally, the address bus is 20-bits, and the data bus is 16-bits for the 8086 and 8-bits for the 8088.The data bus in the 8086 is 16 bits in size, while the address bus is 20.
Multiprocessors have a single physical address space (memory) shared by all the CPUs whereas multicomputers have one physical address space per CPU Multiprocessors have a single physical address space (memory) shared by all the CPUs whereas multicomputers have one physical address space per CPU