The minimum size of an address bus depends on the amount of memory the system needs to access. To calculate the minimum size, you can use the formula (2^n), where (n) is the number of bits in the address bus and determines the number of unique addresses it can generate. For example, a 32-bit address bus can address (2^{32}) locations, or 4 GB of memory. Therefore, the minimum size of the address bus must be large enough to accommodate the maximum memory requirement of the system.
The address bus in the 8085 is 16 bits wide.
The 8086/8088 has an internal 20-bit address bus and 16-bit data bus. Externally, the address bus is 20-bits, and the data bus is 16-bits for the 8086 and 8-bits for the 8088.The data bus in the 8086 is 16 bits in size, while the address bus is 20.
It depends on the size of the address bus, which is often different than the size of the data bus.If the address bus were 8 bits, then you could address 256 locations.If the address bus were 16 bits, such as in the 8085, then you could address 65,536 locations.If the address bus were 20 bits, such as in the 8086/8088, then you can address 1,048,576 locations.
The size of the address bus affects the maximum amount of memory a computer can directly access. Specifically, it determines the number of unique memory addresses that can be generated, which is calculated as 2 raised to the power of the address bus size (in bits). For example, a 32-bit address bus can address up to 4 GB of memory, while a 64-bit address bus can theoretically access 16 exabytes. Thus, a larger address bus allows for greater memory capacity and can enhance overall system performance.
It depends on the size of the bus
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size of the address bus
A memory with a 16 bit address bus can address 216 or 65536 distinct items. If each item is 32 bits in size, then the item is 4 bytes. The size of this memory is then 262144 bytes. (256Kb)
The data bus in the 8086 is 16 bits in size, while the address bus is 20 (16bits would only address 64KB of memory, an extra 4 bits allows to address the total of 1MB, this is done trough segmentation of the memory). To form a multiplexed of data bus and address bus, four bits of 8086 address bus are grounded.
address bus
The data and address buses are multiplexed in order to save pin count on the chip. In the first clock cycle of a read or write cycle, the address is emitted on the address/data bus. The ALE signal is used to strobe the address, after which the address/data bus becomes the data bus. External logic is expected to strobe the address at the trailing edge of ALE. ALE is generated directly by the 8085, and by the 8086/8088 in minimum mode. In maximum mode in the 8086/8088, ALE is generated by the 8288 Bus Controller.
1TB is 240 bytes. It follows that a 40 bit address bus can address 1TB. Since 1TB is 1TB regardless of the system's word size, a 40 bit address bus can address 1TB on a computer with an 8 bit, a 16 bit, a 32 bit, or any other word size.