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What weight of FE3O4 will furnish 0.5430g of FE2O3?
To calculate the weight of Fe3O4 needed to furnish 0.5430g of Fe2O3, you need to consider the molar masses of Fe3O4 and Fe2O3. The molar mass of Fe3O4 is 231.535 g/mol, and of Fe2O3 is 159.69 g/mol. By using the molar ratios between Fe3O4 and Fe2O3, you can determine that 0.5430g of Fe2O3 would require 0.7799g of Fe3O4.
What are the three oxides of iron?
FeO, Fe2O3, Fe3O4 Note: Fe3O4 can be considered as a mixture of FeO and Fe2O3
What is the percent composition of oxygen in the magnetite Fe3O4?
The molar mass of Fe3O4 is 231.55 g/mol. The molar mass of oxygen is 16.00 g/mol. There are 12 oxygen atoms in Fe3O4, so the total mass of oxygen in Fe3O4 is 192.00 g. Therefore, the percent composition of oxygen in Fe3O4 is (192.00 g / 231.55 g) x 100 = 82.97%.
How do you balance the folowing equation Fe H20 --Fe3O4 H2?
Fe3O4 is the mineral magnetite, with aproper chemical name of Fe(II, III) oxide. it exhibits ferrimagnetism. It has iron atoms as FeII and FeIII. An old way of writing it was FeO.Fe2O3 The balanced equation for production from the elements is :- 3Fe + 2O2 -> Fe3O4 Commercially it is made by for example redung Fe2O3 with CO 3Fe2O3 + CO = 2Fe3O4 +CO2
How many moles of fe3o4 are needed to prepare 4.05moles of fe2o3?
To find the moles of Fe3O4 needed, we first need to determine the molar ratio between Fe3O4 and Fe2O3. The balanced chemical equation for the conversion will provide this information. If the equation is Fe3O4 -> 2Fe2O3, then the molar ratio is 1:2. Thus, 4.05 moles of Fe2O3 would require 2 * 4.05 = 8.1 moles of Fe3O4.
What is the chemical compound for magnetite?
Magnetite is Fe3O4.
How many grams of Fe3O4 are required to react completey with 300 grams of H2?
The balanced chemical equation for the reaction between Fe3O4 and H2 is: Fe3O4 + 4H2 -> 3Fe + 4H2O From the equation, it can be seen that 1 mole of Fe3O4 reacts with 4 moles of H2. Calculate the moles of H2 in 300g, then use the mole ratio to find the moles of Fe3O4 needed. Finally, convert the moles of Fe3O4 to grams using its molar mass to determine the amount required.
FeO and FE3O4 react to form 5.779g of Fe2O3 What is the percent by mass of FeO if Feo and Fe3O4 is 5.280g.?
just apply poac on both the sides and get the solution
Is Fe3O4 a compound or element?
Fe3O4 is a compound. It is known as iron(II,III) oxide, where iron atoms are present in a combination of +2 and +3 oxidation states with oxygen.
What is the chemical formula for oxygen and iron III?
Fe3O4 (The numbers are subscripts, meaning they are smaller, and go beside the element.)
How many moles of iron can be recovered from 100.0 kg of Fe3O4?
Well first things first you have to balance the equation Fe3O4-->3Fe+2O2 Then because your given mass is in kg you have to convert it to grams 100.0kgx1,000kg/(over)1g=100,000g or 1.0x105 Next because you have mass of Fe3O4 you need to get the molar mass. (3)55.85gFe+(4)16.00gO=231.55gFe3O4 Now convert grams to moles for your final answer 1.0x105gFe3O4x1mol/(over)231.55g(mm)x3molFe/(over)1mol Fe=1295.6 mol Fe you can recover 1295.6moles of Fe from Fe3O4 If you follow the rule of Significant Figures, 100.0kg has 4 significant figures (digits) so your answer needs to have 4 digits 1295.6=1296 you can recover 1296 moles of Fe from Fe3O4
How do you balance Fe H2O---Fe3O4 H2?
To balance the equation Fe + H2O → Fe3O4 + H2, you need to ensure the number of atoms of each element are equal on both sides. Start by balancing the iron atoms, then balance the oxygen atoms, and finally balance the hydrogen atoms. The balanced equation is 3Fe + 4H2O → Fe3O4 + 4H2.
