In a vacuum (i.e. neglecting air resistance) a falling object would reach a speed of about 124.2 m/s (278 mph) in falling 828 m. However, in an average configuration, a coin would reach terminal velocity at about 18.7 m/s (42 mph) and take approximately 45 seconds to reach the ground from 828 m. Edge on, it could reach 29 m/sec (65 mph) and be on the ground in just 31 seconds.
Note that you cannot drop a coin straight down, but would have to throw it outward a distance of at least 15 m (50 feet) to reach the ground.
*Base jumpers who jumped from the top of the building (2717 feet) took about 80 seconds to reach the ground including 10 seconds of freefall.
A penny dropped from the top of a skyscraper would reach the ground in approximately 9.2 seconds. A passerby on the sidewalk below would have less than 9 seconds to move out of the way once they see the penny falling.
If you drop a penny off the Empire State Building, it falls at its own terminal velocity after falling about 200+ metres (that's a guess but it's around 200). A penny's terminal velocity is roughly half of a falling person's terminal velocity. A falling skydiver will reach a maximum of around 130mph, so a penny will fall at approximately 65mph.
The penny will be gone. You will also be gone with it, because getting close enough to a black hole to drop a penny inside it will catch you in its gravity well.
Yes
it would be 7
If a penny and a text book were dropped in a vacuum then they will both hit the ground at the same time. This refers to Newton's laws. If they are dropped at the same time on earth then the text book would hit the ground first.
I say NO. If you mean it is dropped and falls vertically. Discover Channel's "Myth Busters" tried to determine if a bullet would kill you if it was fired directly vertical and falls on its own. The bullet or penny would fall at terminal velocity which is about 120mph. However, they will tumble which slows them down more. This velocity and their mass is not enough to kill you.
The penny will zig zag till it hits the bottom, the same way a a piece of paper would if you held it up and dropped it. It would be easier to drop a marble or a pebble.
If it dropped from a high enough distance, it would if its terminal velocity were higher than the speed necessary to kill a person. Since coins are small and more aerodynamic, the terminal velocity would be higher than a larger, flatter object, making it sort of like a bullet. The weight of a penny would be a function of it's acceleration. If the penny is still, that acceleration would be that of gravity, more or less 9,8 m/s.s or 1 G. You take the mass of a penny (in kg) and multiply it by the acceleration (in m/s.s) to get the weight in Newtons (which is force). So, a falling penny would be going 9,8 m/s faster every second before reaching its terminal velocity. The main point is the final velocity will be very high since it's a small and for all practical purposes, an aerodynamic object and therefore the kinetic energy will be very high as well. So will the force, which depends on the acceleration and the Work, which will be the very high transference of energy from the penny to somebody's head.
If the penny is in a vaccum, the penny has no terminal velocity because verminal velocity is when the resistance against the falling penny is equal to the force of gravity. So if it is in a vaccum, it has no forces resisting the fall, and it has no terminal velocity.
If there was no air resistance and a feather and a penny were dropped from the same height they would both pick up speed by the same amount and they would hit the ground at the same speed and at the same time.
A penny dropped from the Empire State Building would not be worth much more than its face value of one cent. Due to air resistance, it reaches a terminal velocity of about 25 mph, meaning it wouldn't gain enough speed to cause significant damage upon landing. While it might create a small impact, it’s unlikely to be lethal or highly valuable; the penny would simply land as a standard coin.