K2B with 1s typically refers to a specific notation or abbreviation in a particular context, but it's not a widely recognized term. It could represent a variety of things depending on the field, such as a mathematical expression, a programming code, or a shorthand in a specific industry. More context is needed to provide a precise interpretation.
To find the rate constant (k) of the reaction, we can use the rate equation: Rate = k[A]^m[B]^n. Given that the rate is (1 \times 10^{-2} , \text{(mol L)}^{-1} , \text{s}^{-1}), [A] = 2 M, [B] = 3 M, m = 2, and n = 1, we substitute these values into the equation: [ 1 \times 10^{-2} = k \cdot (2^2) \cdot (3^1) ] This simplifies to: [ 1 \times 10^{-2} = k \cdot 4 \cdot 3 \implies 1 \times 10^{-2} = k \cdot 12 ] Solving for k gives: [ k = \frac{1 \times 10^{-2}}{12} \approx 8.33 \times 10^{-4} , \text{(mol L)}^{-1} , \text{s}^{-1} ]
The rate law for this reaction is rate = k[A]^m[B]^n. From the given information, substituting the values for rate, [A], [B], and the exponents m and n, you can solve for the rate constant k. In this case, k = rate / ([A]^m[B]^n), so k = 2 / (10^2 * 3^1).
0.4 (mol/L)/s
To determine the rate of the reaction that follows the rate law rate = k[A]^m[B]^n, where k = 3 M^(-2) s^(-1), [A] = 2 M, and [B] = 3 M, we first need to substitute these values into the rate law. Given that m = 2 and n = 3, the rate can be calculated as follows: Rate = k[A]^m[B]^n = 3 M^(-2) s^(-1) * (2 M)^2 * (3 M)^3 = 3 * 4 * 27 = 324 M/s. Thus, the rate of the reaction is 324 M/s.
Rock, thicko
k*S + (1-k)*T where k is any number between 0 and 1.
eqb constant k For a general EQN A+B=S+T the equilibrium constant can be defined by[1] k={S}{T}/{A}{B} {S} = MOLAR CONC. OF S{T} = MOLAR CONC. OF T{A} = MOLAR CONC. OF A{B} = MOLAR CONC. OF B
If 'r' and 's' can be the same integer, then (1)3 = (1)2 , and k = 1 .If 'r' and 's' must be different integers, then (4)3 = (8)2 , and k = 64 .
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The rate law for the reaction is given by Rate = k[A]^m[B]^n. Plugging in the given concentrations and rate into the rate law, we have 10^-2 = k*(2)^2*(3)^1. Solving for k gives k = 10^-2 / (43) = 10^-2 / 12 = 8.33 x 10^-4 L/mols.
B. K. S. Iyengar was born on December 14, 1918.