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What is the rate constant of a reaction if rate 1 x 10-2 (MolL)s A is 2 M B is 3 M m 2 and n 1?
To find the rate constant (k) of the reaction, we can use the rate equation: Rate = k[A]^m[B]^n. Given that the rate is (1 \times 10^{-2} , \text{(mol L)}^{-1} , \text{s}^{-1}), [A] = 2 M, [B] = 3 M, m = 2, and n = 1, we substitute these values into the equation: [ 1 \times 10^{-2} = k \cdot (2^2) \cdot (3^1) ] This simplifies to: [ 1 \times 10^{-2} = k \cdot 4 \cdot 3 \implies 1 \times 10^{-2} = k \cdot 12 ] Solving for k gives: [ k = \frac{1 \times 10^{-2}}{12} \approx 8.33 \times 10^{-4} , \text{(mol L)}^{-1} , \text{s}^{-1} ]
What is the rate constant of a reaction if rate 1 10 2 mol L s A is 2 M B is 3 M m 2 and n 1?
The rate law for this reaction is rate = k[A]^m[B]^n. From the given information, substituting the values for rate, [A], [B], and the exponents m and n, you can solve for the rate constant k. In this case, k = rate / ([A]^m[B]^n), so k = 2 / (10^2 * 3^1).
What is the rate of a reaction if the value of k is 0.1 A is 1 M and B is 2 M?
0.4 (mol/L)/s
What is K-2 made of?
Rock, thicko
Which number is between point S and point T on the number line?
k*S + (1-k)*T where k is any number between 0 and 1.
Find equilibrium constant of the reaction?
eqb constant k For a general EQN A+B=S+T the equilibrium constant can be defined by[1] k={S}{T}/{A}{B} {S} = MOLAR CONC. OF S{T} = MOLAR CONC. OF T{A} = MOLAR CONC. OF A{B} = MOLAR CONC. OF B
What is 1 2 B your S?
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What is 1 B 2 S?
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What is B. K. S. Iyengar's birthday?
B. K. S. Iyengar was born on December 14, 1918.
When was B. K. S. Iyengar born?
B. K. S. Iyengar was born on December 14, 1918.
What has the author S B K Anderson written?
S. B. K. Anderson has written: 'Saint Kyneburgha'
What is the smallest integer k such that r3 equals s2 equals k where are and s are positive integers?
If 'r' and 's' can be the same integer, then (1)3 = (1)2 , and k = 1 .If 'r' and 's' must be different integers, then (4)3 = (8)2 , and k = 64 .
