The most common product of the reaction is ammonia, NH3, but it is a uncommon reaction in nature, but this one of the most produced chemical in the world (for fertilizer).
Equation:
N2 + 3H2 ---> 2NH3
This reaction is uncommon in nature because it can only form under the Haber-Bosch Process, which require a large activation energy, high pressure, and a catalyst.
The reactants are hydrogen and nitrogen.
True, the balanced equation N2 + 3H2 -> 2NH3 shows that 1 mole of N2 reacts with 3 moles of H2 to form 2 moles of NH3. From the molar masses of N2 (28g/mol), H2 (2g/mol), and NH3 (17g/mol), it can be calculated that 1g of N2 reacts with 3g of H2 to form 2g of NH3.
H2 and NO can react to form H2O and N2. This reaction occurs at high temperatures in the presence of a catalyst.
(N2) + 3(H2) = 2(NH3)
The reaction between nitrogen and hydrogen to form ammonia is: N2 + 3 H2 → 2 NH3 The above is the reaction for the Haber process in the industrial synthesis of ammonia. For a given proportion of 3 N2 to 2 H2 (or in ratio terms equivalent to 4.5 N2 to 3 H2), we see that H2 is the limiting reactant. Thus according to the stoichiometry of the reaction, 2 moles of H2 will form 1.33 moles of NH3.
The chemical reaction is:N2 + 3 H2 = 2 NH3For six molecules of nitrogen N2 18 molecules of hydrogen H2 are needed.
The reaction of 2 liters of N2 and 2 liters of H2 to form NH3 is based on the balanced equation: N2 + 3H2 -> 2NH3. Since 1 mole of N2 reacts with 3 moles of H2 to form 2 moles of NH3, 2 liters of N2 and 2 liters of H2 would produce 2 liters of NH3 following the stoichiometry of the balanced equation.
In the reaction N2 + 3H2 → 2NH3, nitrogen (N2) is reduced because it gains hydrogen atoms, and hydrogen (H2) is oxidized because it loses electrons.
To calculate the amount of H2 needed for the complete reaction with 7.1g of N2, you need to use the stoichiometry of the balanced chemical equation. Since the reaction is not specified, I'll assume it's the formation of ammonia (NH3) from N2 and H2. Using the balanced equation, calculate the molar ratio of N2 to H2. Then convert 7.1g of N2 to moles, and finally use the molar ratio to determine the grams of H2 required.
N2 + 3H2 ==> 2NH3
Three: The reaction equation is N2 + 3 H2 -> 2 NH3
A diatomic acompound such as HF, HCl, or CO. H2, N2, and O2, are not compounds.