A 150 HP electric motor will have approximately 280 foot pounds of torque output. Torque is used mostly at low speeds to get loads moving.
YES
Torque for 50 hp fore stroke casing bolts
Horsepower is 150 @ 3800RPM and torque is 240 @ 2400RPM
160 hp and 185 ft pounds torque
Advertised Horsepower is--245 HP @ 3800 RPMs. Torque is-365 FT. LBS. @ 2800 RPMs. The Heavy Duty 454 has--240 HP @ 3800 RPMs. Torque is--370 FT. LBS. @ 2800 RPMs.
To determine the size of the hydraulic motor needed to be equal to a 3 hp electric motor, you would need to calculate the hydraulic motor's power output in horsepower. Hydraulic motors are generally less efficient than electric motors, so you may need a larger hydraulic motor to match the power output of a 3 hp electric motor. Consult the manufacturer's specifications and consider factors such as efficiency and operating conditions.
It has 220 hp and 221 pounds of torque
125 hp and 107 ft lbs of torque.
Horsepower (hp) and revolutions per minute (rpm) are related but not directly convertible without additional information, such as the torque of the motor. Specifically, 1 horsepower is equivalent to 5252 foot-pounds per minute when torque is expressed in foot-pounds. To find the rpm for a 2 hp motor, you would need to know the torque; the formula is: hp = (torque in lb-ft × rpm) / 5252. Thus, without the torque value, you cannot directly calculate rpm from horsepower.
No, you cannot use a starter rated for a 5 hp motor with a 7.5 hp motor. The starter needs to be matched to the motor's horsepower rating to ensure proper protection and operation. Using an undersized starter can lead to overheating and premature failure of the motor. It is recommended to use a starter specifically designed for a 7.5 hp motor.
It is a short-hand description of the torque from a 3-phase motor. By the nature of 3-phase electricity, a motor using it gives a constant torque, unlike a single-phase motor which gives a torque that pulsates at twice the supply frequency. Usually that does not matter because there is enough inertia in the rotating parts to mask the effect.