tell me more about the gun- does it say dm lefever? what guage? any other details so I can deturmin its age
Paul endever4us@aol.com
serial #1728 was a DM Lefever made around 1903 in Defiance Ohio or Bowling Green Ohio I have been collecting these guns for 30 years feel free to call me at 419-450-2454 Ohio for some free advise ! Paul
the cube root of 1728 is 12
To find the number that, when multiplied by itself three times, equals 1728, you need to calculate the cube root of 1728. The cube root of 1728 is 12, since 12 × 12 × 12 = 1728. Therefore, the number is 12.
The expression "radical -1728" refers to the square root of -1728, which is not a real number because you cannot take the square root of a negative number in the realm of real numbers. In the context of complex numbers, it can be expressed as ( \sqrt{-1728} = \sqrt{1728} i = 12\sqrt{12} i ). Cubing this value, ( (12\sqrt{12} i)^3 = 1728\sqrt{12^3} i^3 = -1728 \cdot 12\sqrt{12} = -20736\sqrt{12} ). Thus, the cube of the square root of -1728 is a complex number.
The number 12.
1728 is even so it cannot have an odd cube root.
1728 is a pure number. Without units it has no meaning in volumetric measurements.
1728/60=28 and left 48number is written as 28,48
To determine if 1728 is divisible by 6, we need to check if the sum of its digits is divisible by 3 and if it is an even number. The sum of the digits of 1728 is 1+7+2+8=18, which is divisible by 3. Additionally, the last digit of 1728 is 8, which is an even number. Therefore, 1728 is divisible by 6.
It is: 12*12*12 = 1728
3√1728 = 12
24√3 or 41.5692194 or 41.57, to the justified number of significant digits since 1728 has only four.
it is 1728. plz check wikipedia for confirmation.