Sulphur dioxide has 2 sigma bond electron pairs and 1 lone pair of electrons, meaning the shape is V-shaped, or bent. There is extra repulsion from the lone pair of electrons, so the bond angle is a little smaller than 120 degrees. - 119 degrees is the answer.
Sulfur dioxide is a bent molecule with two lone pairs. The sulfur atom is directly bonded with two oxygen atoms on the same plane. According to the VSEPR theory, it has a bond angle of 91 degrees.
The sulfate ion when in solution has a tetrahedral geometry- and therfore a bond angle of 109.5 degrees
The sulfate ion is tetrahedral with shape. It has no lone pairs located on the central atom, sulfur. Therefore, every bond angle in the sulfate ion is approximately equal to 109.5 degrees.
Bond angle 119 0. Picture in link
119 degrees for the OSO bond angle
91.5
109.5
Increases
Bond angle is 109.5 degrees.It is equal in every bond
NH4+ is tetrahedral, with bond angle of 109.5o
the f-p-f bond angle is 120the cl -p-cl bond angle is 180and the f - p - cl bond angle is 90
Ionic compound, with ionic bond between Cu2+ and SO42- ions.
Increases
Bond angle is 109.5 degrees.It is equal in every bond
NH4+ is tetrahedral, with bond angle of 109.5o
the f-p-f bond angle is 120the cl -p-cl bond angle is 180and the f - p - cl bond angle is 90
Ionic compound, with ionic bond between Cu2+ and SO42- ions.
Bond Angle (:
The bond angle for H2S is 92.1­°.
The water molecule's bond angle is about 104.45 degrees.
the shape is bent and the bond angle is approximately 120
No, the bond angle for linear structure is 180 degrees.
The answer would be bond angle, for number 19#
The question is nonsense. WHICH bond angle? There are many of them in a molecule the size of estradiol.