no because f orbitals are not energetically available until the n=4 quantum state
No
no
No... it orbital 2d does not exist.
The s orbital is present in all valid principal quantum number shells.The p orbital is present in n = 2 and higher.The d orbital is present in n = 3 and higher.The f orbital is present in n = 4 and higher.So the invalid ones are b (there are no 2d orbitals) and c (there are no 3f orbitals). 4s and 3p are perfectly legitimate.
The Angular Momentum Quantum number L, defines how many types of orbitals can exist. For a particular Quantum Level n, L is defined as any integer from 0 to L = n-1. For example, for the energy level n = we must have, L = 0 or 1. L=0 relates to the s-orbital L=1 relates to the p-orbital L=2 would relate to the d-orbital, but we can see here that for n=2, L cannot = 2
3f can not exist by the Aufbau principle, quantum mechanics and Hunds rules. In level one there is only 1s In level 2 there is 2s and 2p In level 3 there is 3s, 3p and 3d Only in level 4 and beyond is there an f shell. In level 4 there is 4s, 4p, 4d and 4f. The 4f can hold up to 14 electrons.
The three dimensional region around the nucleus of an atom that indicates the probability of the location of an electron is called an orbital. Different orbitals exist in atoms depending on the number of electrons the atom possesses. The element hydrogen only has one orbital, whereas heavier elements such as radon have many.
3f
There can be a maximum of 14 electrons in any "f" orbital. However, the 3f orbital does not exist. f orbitals are only found in quantum energy level 4 and above.
3f ( 3 only has the d orbital final ) and 2d ( 2p is the final orbital on the 2 level )
no
No... it orbital 2d does not exist.
2d is incorrect
3f
The s orbital is present in all valid principal quantum number shells.The p orbital is present in n = 2 and higher.The d orbital is present in n = 3 and higher.The f orbital is present in n = 4 and higher.So the invalid ones are b (there are no 2d orbitals) and c (there are no 3f orbitals). 4s and 3p are perfectly legitimate.
Molecular orbitals: dihelium has two electrons in the bonding orbital and two in the antibonding orbital. That why it does not exists.
-3f - 14 = 1 -3f = 1+14 -3f = 15 f = -5
The Angular Momentum Quantum number L, defines how many types of orbitals can exist. For a particular Quantum Level n, L is defined as any integer from 0 to L = n-1. For example, for the energy level n = we must have, L = 0 or 1. L=0 relates to the s-orbital L=1 relates to the p-orbital L=2 would relate to the d-orbital, but we can see here that for n=2, L cannot = 2
Too many to list: [http://onelook.com/?w=%3F%3F%3F%3F%3F%3Fx&ls=a try this link]