The US system is not a two-phase system; it's a split-phase system. But, to answer your question, probably not without damaging the Japanese device.
In a three phase that means there are three lines live. Lets name the first line L1, second one L2 and the last L3. If you would connet it to a three phase motor then you require L1, L2 and L3 to be connected either in star or delta connection. Rating of your motor should be 200V, 3 phase , x HP ( star or delta connected). If you have a single motor of 200V then you only need to connect two lines of the three., namely either L1 to L2 , L1 to L3 or L2 to L3.
Put the meter on AC Volts, 200V range. For residential US service you should have 120V between hot and neutral, 120V between hot and ground, and 0V between neutral and ground. Remember: narrow prong is hot, wide prong is neutral, round prong is ground. Don't set your meter to current or you will zap it. Reisitance shouldn't damage it, but the reading will be worthless. (If you don't know what you are testing for or how to use your tool, should you really be sticking things in a wall outlet?)
Yes, you'd have to change the plug or use an adapter, and also change the bulb. Thry make the standard "medium base" A19 bulbs in 220v also. here's a few: http://www.bulbs.com/Light_Bulbs/Medium_(E26)/200V+-/results.aspx
About 5000 volts. Additional Explanation of this answer While the "Striking Voltage" of the Bulb may be 5,000 + volts the bulb actually operates on much less. More like 120V or 200V. If you continued using 5,000 V the bulb would rapidly burn itself out. The striking voltage is much like a Florescent bulb. The higher voltage is to cause a spark between the gaps or electrodes to ignite the gasses within the bulb regardless of Florescent , High Pressure Mercury or any similar bulb, then the voltage lowers to keep the bulb lit. This is exactly the reason they need a Ballast, Starter or similar device to start the bulb Hopefully this answer helps others We decided to edit the other persons answer to further explain and to help avoid and injuries or damages caused by improper voltage Electronic Surplus Div or Replacement Tv Parts
In a three phase that means there are three lines live. Lets name the first line L1, second one L2 and the last L3. If you would connet it to a three phase motor then you require L1, L2 and L3 to be connected either in star or delta connection. Rating of your motor should be 200V, 3 phase , x HP ( star or delta connected). If you have a single motor of 200V then you only need to connect two lines of the three., namely either L1 to L2 , L1 to L3 or L2 to L3.
In most applications 200v is easier to get for a supply voltage than 380v.
current flows in both directions, depending on the AC voltage, i.e when ac is higher, current flows to the dc side, and vice versa
what is the correct fuse rating to provide short-circit protection for a100 HP 200V 3-0 wound-rotor motor
80
200V / 240V 5 / 6
For a sine wave ONLY - and assuming you are talking plus and minus 100V (200V peak to peak) - the RMS voltage is about 71V. (One half square root of 2 * single sided peak value)
By doing math 200v reduce by one half is 100v pk or .639 vlots average or 63volts ac.
The current through a pure, or ideal, inductor having zero resistance, would lag the voltage with a phase angle of 90 degrees. The inductive reactance of a 1 Henry inductor at 60 hz is about 380 ohms. XL = 2 * pi * f * L so 200 volts at 380 ohms is about 0.53 amps and the power drawn, using the basic Power equation: power = volts * amps, would be about 105 vars. Var is the correct term for volts times amps, or volt-amp-reactive, where we consider the phase angle to be 90 degrees.
I[A] = U[V] / R[ohms] (Ohm's law)so, 200V / 100ohms = 2A.Incidentally, that resistor needs to do something about the 400W of power it needs to handle (2A * 200V = 400W)... ;-)Unless, of course, it's a resistive wire, and the whole device is an electric heater... Then I guess it doesn't need to worry about the extra heat. Still, that's 48Ahours (or 9.6kWh) in a day, right there. That's $46.59 just in power costs for running that thing for 30 days straight, in California.
Most of the typical Windows operating systems work with the BT Voyager 200V modem. This includes Windows 98, Windows 2000, Windows XP, and Windows NT 4.
There is no voltage in three phase wire. The ability of wire to carry voltage is dependant upon the insulation that surrounds the wire. The thicker the insulation the higher the voltage potential can become. Three standard insulation voltages are 300, 600 and 1000 volts.Another AnswerFirst of all, there is no such thing as a voltage 'on' a wire. 'Voltage' is another word for 'potential difference', so a voltage can only exist between two wires. Voltages in three-phase systems are generally specified in terms of their line voltages-i.e. the voltage between any two line conductors. These depend on the electrical standards used in the country in which you live. In the UK, for example, three-phase transmission lines will have line voltages of 400 kV, 275 kV, or 132 kV, while distribution lines will have line voltages of 33 kV and 11 kV, and low-voltage distribution line voltage is 400 V.