0
52.1grams.
moles = mass (in grams)/RMM (relative molecular mass)
1.3 moles = mass (in grams)/ 40.078
mass = 40.078 x 1.3 = 52.1grams
Wiki User
∙ 13y ago
Add your answer:
Earn +20 pts
How many grams of oxygen are required to burn 4.8 mol of butane?
The balanced equation for the reaction is 2 C4H10 + 13 O2 -> 8 CO2 + 10 H2O. This shows that 13 moles of diatomic oxygen are required to burn 2 moles of butane. By proportionality, (4.8/2)13 or 31.2 moles of oxygen are required to burn 4.8 moles of butane. This corresponds to 31.2(32) or 1.0 X 103 grams of oxygen.
How many moles of carbon are in 10.5g of ibuprofen?
The formula of Ibuprofen is: C13H18O2 The molar mass is: 13x 12.01= 156.13 g/mol of C 18x1.008 = 18.144 g/mol of H 2x16.00 = 32.0 g/mol of O Total: 206 g/mol of ibuprofen
How many atoms are in 9.00 grams of carbon 13?
9.00 grams carbon 13 ( 1 mole C13/13.00355 grams)(6.022 X 1023/1 mole C13) = 4.17 X 1023 atoms of carbon 13 -------------------------------------------
Convert 13 C degrees into Fahrenheit?
13 C = 55.4 F
What is the formula mass of Na2CO3.10H2O?
This is not difficult if you remember the meaning of numbers in different positions. The correct format is Na2CO3.10H2O (sodium carbonate decahydrate). The subscripts multiply only the element immediately before them, and the 10 multiplies the whole water molecule. Thus we have:sodium, Na, 2 moles of atomscarbon, C, 1 mole of atomsoxygen, O 3 moles of atomswater, H2O, 10 moles of molecules, i.e. 20 moles of hydrogen atoms, H, and 10 moles of oxygen atoms, O.Collecting these we have 2 moles Na, I mole C, 13 moles O and 20 moles of H.We find the formula mass by multiplying each element's number of moles by its mole mass and adding them all up:r.f.m = 2 x 23 + 12 +13 x 16 + 20= 286.
How many moles of atoms are in 8 grams of carbon 13?
0,666 moles
How many ounce in 13 grams?
13 ounces = 368.54 grams. The formula to convert 13 ounces to grams 13 oz* 28.34952313 g 1 oz = 368.5438006 g
How many grams of oxygen are required to burn 4.8 mol of butane?
The balanced equation for the reaction is 2 C4H10 + 13 O2 -> 8 CO2 + 10 H2O. This shows that 13 moles of diatomic oxygen are required to burn 2 moles of butane. By proportionality, (4.8/2)13 or 31.2 moles of oxygen are required to burn 4.8 moles of butane. This corresponds to 31.2(32) or 1.0 X 103 grams of oxygen.
How many moles is 3 grams of carbon?
By definition, one mole would be the same as the atomic mass. You take the number of moles and multiply it by the atomic mass. So if you have just 1 mole, the number of grams will be the atomic mass. Carbon's atomic mass is 12.011 grams.
How many moles of atoms are in 9.00g of carbon 13?
Formal set up. ( Avogadro's number appears as form of 1 here ) 9.00 grams 13C (1 mole 13C/13.00 grams)(6.022 X 1023/1 mole 13C)(1 mole atoms 13C/6.022 X 1023) = 0.692 mole of 13C atoms ====================
How many moles are present in 500.00 g of H2O?
For this you need the atomic (molecular) mass of H2O. Take the number of grams and divide it by the atomic mass. Multiply by one mole for units to cancel. H2O= 18.0 grams500.0 grams H2O / (18.0 grams) = 27.8 moles H2O
How much is 13 oz in grams?
13 ounces = 368.54 grams. The formula to convert 13 oz to grams: 13 oz* 28.34952313 g 1 oz = 368.5438006 g
How much 75.66MKCL is required toprepare 1L of solution?
I did not know that you could get a concentration of 75.66 M KCl, but; Molarity = moles of solute/Liters of solution 75.66 M KCl = moles KCl/1 liter = 75.66 moles of KCl 75.66 moles KCl (74.55 grams/1 mole KCl) = 5640 grams KCl that is about 13 pounds of KCl in 1 liter of solution. This is why I think there is something really wrong with this problem!
Convert to grams 1.3 kilogram?
13 Grams divided by 1000 = 0.13 Kilograms So .013 Kilo grams is your answer! (:
How many g is 13 oz?
13-oz is 368.54 grams. Download the Freeware program called Convert, it can answer just about any conversion question you may have.
The density of a glass marble that has a volume of 5 cubic centimeters and a mass of 13 grams is?
Denisty = mass/volume. 13/5 and then convert your units as need be.
How many grams of Al2S3 can be formed from the reaction of 108.00 grams of Al with 5.00 grams of S?
The answer i got is 12.33 grams of Al2S3. Below i will try to show the steps i used: n=moles m=mass (grams) M= molecular weight (from periodic table) 2Al + 3S --> Al2S3 nAl= m/M = 9/13 = 0.692307 moles of Al nS= m/M = 8/16 = 0.5 moles of S Limiting Reagent: 1.5 moles of S required for every mole of Al (3:2 ratio) This means that there should be about 1.04 moles of S to completely use up all the Al. Since there is less than this amount of S present (only 0.5 moles), S is the limiting reagent and should be used in the mole calculation of the product Amount of product: 0.5 moles S x (1 mol Al2S3/ 3 mol S) = 0.16666 moles of Al2S3 nAl2S3 = m/M Molecular weight of Al2S3 = (2 x 13) + (3 x 16) = 74 0.16666 moles Al2S3 = m/74 m = 74 x 0.16666 = 12.33 grams of Al2S3 Therefore, 12.33 grams of Al2S3 is formed in this reaction ( hopefully this is right :P )
