no, but the electromagnetic field of the earth does.
No. Acceleration due to gravity is constant no matter where an object is because gravity depends on mass. The mass of the earth is not greater or less at the poles than it is at the equator.
The closer an object gets to the center of the earth, the greater the pull of gravity on that object.
Gravity on Earth is slightly stronger at the poles than at the equator, because the diameter of the Earth at the equator is larger than the diameter through the poles. So when you stand at a pole, you're closer to the center of the Earth, and that's the distance that determines the force of gravity between you and the Earth.
Gravity increases from about 9.780 m/s2 at the Equator to about 9.832 m/s2 at the poles. This means an object will weigh about 0.5% more at the poles than at the Equator.
The bulging Earth has more surface "gravity" at its equator.
since gravity is inversly proportional to square of radius. Gravity increases with equater to poles. Gravity is high on poles and less on equator
Since the earth is spinning ... an object on the equator is moving roughly 1,000 miles per hour ... the earth is somewhat bulged at the equator. Its diameter at the equator is a little larger than the distance between the north and south poles. For that reason, when you stand at the pole, you're a bit closer to the center of the earth than when you stand on the equator. The farther you are from the center of the earth, the lower the force of gravity between you and the earth. So the force is less at the equator and more at the poles.
The equation for the force of gravity is F=-GMm/r2 at the equator the earth has more mass due to the gravity of the sun distroting the sherical shape of the earth. But this mean that the distance between the centre of the earth to the poles (r) is less and because r is squared the effect of distance has more of an impact than the mass so this means that gravity is stronger at the poles and weaker at the equator.....
It is greater at poles than at equator.
Well, I think it will swing faster in the equator than at the poles because T=sq. root l/q says that when the gravity increases, the time decreases and when the gravity decreases time increases. Thus it will swing slower at the poles than in the equator
The earth is not a perfect sphere. The spin of the earth causes it to buldge out at the equator, which means the equator is further from the center of the earth then the poles are. The further an object is from the center of mass of another object, the less effect the gravity of those objects will have on each other. So at the equator, an object is being effected less by the gravity of the earth then it is at the poles.
Not for sure but it seems like there would be more gravity at the equator than at the poles. The earth rotates and creates a centrifugal acceleration at the equator the counters the force of gravity. acceleration due to gravity =GM/R2 acceleration due to rotation =V2/R So gravity at the equator is GM/R2 - V2/R
gravity