Actually, a for loop is more appropriate in this case. With while, it would be something like the following pseudocode - adapt to your favorite programming language:
function factorial(n)
result = 1
factor = 1
while factor <= n
{
result *= factor
factor++
}
return result
double factorial(double N){double total = 1;while (N > 1){total *= N;N--;}return total; // We are returning the value in variable title total//return factorial;}int main(){double myNumber = 0;cout > myNumber;cout
#include <iostream> using namespace std; int main() { int i, number=0, factorial=1; // User input must be an integer number between 1 and 10 while(number<1 number>10) { cout << "Enter integer number (1-10) = "; cin >> number; } // Calculate the factorial with a FOR loop for(i=1; i<=number; i++) { factorial = factorial*i; } // Output result cout << "Factorial = " << factorial << endl;
#include #include using std::cin;using std::cout;using std::endl;using std::tolower;long factorial(const int& N);int main(){int N = 0; //factorial of Nchar command = 'n';do{cout > N;cout
// returns n! int fact(final int n) { // keep track of factorial calculation in f // f starts at n, and we will multiply it by all integers less than n int f = n; // loop from n-1 down to 2 for(int i = (n - 1); i > 1; --i) { // increase our total product f *= i; } return f; }
#include #include using std::cin;using std::cout;using std::endl;using std::tolower;long factorial(int N);int main(){int N = 0; //factorial of Nchar command = 'n';do{cout > N;cout
/* gcc -ansi -Wall -Wextra -pedantic -s -static 0.c -o 0 */ #include <stdio.h> int main ( ) { int n , factorial = 1 ; printf ( "enter the value of n\n") ; scanf ( "%i" , & n ) ; while ( n != 0 ) { factorial *= n ; n -- ; } printf ( "The factorial of n is\n%i\n" , factorial ) ; return 0; }
by this program you can find the factorial: #include<iostream> using namespace std; main() { int n,x,f=1; cin>> n; x=0; while(x<n) { x++; f= f*x; } cout<<"factorial is"<<f<<"\n"; system("pause"); return 0; }
//program to find the factorial value f any number using while loop #include<stdio.h> void main() { int i,n,fact=1; printf("Enter the number\n"); scanf("%d",&n); i=n; while (i>=1) { fact=fact*i; i--; } printf("The factorial value=%d",fact); } the above is a program for calculating tha factorial value of any number which is entered by the user
Use this function: long factorial(int N){if (N == 0){return 1;}else{return N*factorial(N-1);}}
report zbharath. data:num type i value 5, fac type i value 0. perform fact using num changing fac. write:/ 'factorial of',num,'is',fac. form fact. using value(f-num) type i. changing f-fact type i. f-fact=1. while f-num ge 1. f-fact=f-fact*f-num. f-num=f-num-1. endwhile. endform.
#include<stdio.h> #include<conio.h> void main() { int i,n,fact=1; clrscr(); printf("enter the number"); scanf("%d",&n); for(i=1;i<=n;i++) printf("%d",n); fact=fact*i; { printf("the factorial is=%d",fact); } getch(); } By:-Abhishek Goyal(goyal.abhi40@yahoo.com)
== == using recursions: unsigned int Factorial( unsigned int x) { if(x>0) { return ( x * Factorial(x-1)); } else { return(1); } } factorial: unsigned int Factorial( unsigned int x) { unsigned int u32fact = 1; if( x == 0) { return(1); } else { while(x>0) { u32fact = u32fact *x; x--; } } }