dissolve 1.25g of cycloheximide in 10ml of alcohol or any desired solution. Now the concentration is 125mg / ml.
26.8125 g
.01 M
12.5
A 5% sucrose solution has 5 grams of sucrose in every 100 grams of solution. As 1mL of water has a mass of 1 gram, you should dissolve 5 grams of sucrose in 95 mL of water.
The answer is 124,93 g (for the anhydrous CaBr2).
25 mL
simply dissolve 5 ml of salt in 250 ml of warm water
26.8125 g
28 gram. = 2 * 56 * 250 / 1000
Weight 150 mg sodium chloride and dissolve in 250 mL water.
RMM of CuSo4 . 5H2O = 160 + 5x18 = 250 g How much contain gram in 100 mL of 0.050 M CuSO4 solution is - Solution: = 0.050 x 100/1000 x 250 = 0.050x4 (100)/ 16 = 1.25 g
If you mean 100 ml of 1 mM CuSO5.H2O, then dissolve 0.1 mmole CuSO4.H2O in sufficient water to make a final volume of 100 ml.molar mass CuSO4.5H2O = 250 g/mole 250 mg = 1 mmole 25 mg = 0.1 mmol Dissolve 25 mg in final volume of 100 mls
2.538g in 1000ml. If you are making this for a titration, like for SO2 or thiosulfate, you need also to add iodide: 1. dissolve 8 g potassium iodide in about 250 mL water. 2. add 2.538 g iodine to the water solution. Stir until dissolved. 3. transfer to a 1000 mL volumetric flask and Q.S. to 1000 mL You should standardize vs. thiosulfate or arsenious oxide.
You don't have to make 1 liter of solution. You can dissolve any equivalent amount of citric acid in a correspondingly equivalent volume of solution. So, 1 mole in 1 liter of solution will make 1 M solution, but so will 0.5 moles in 500 ml or 0.25 moles in 250 mls, etc.
Chlorosulfonic acid, or chlorosulfuric acid, has the formula HSO3Cl. That means I mole is 116.5 g. To make a 0.5 M solution, you need to weigh out 29.167 g of the acid and transfer it, with washings to a 250 ml graduated flask. Make it up to the mark with de-ionized water, ensuring that there is thorough mixing.
20 g alkali to 250 cm3 solution is more concentrated.
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