you can start like I did with simply replacing the stock air filter with a reusable and washable K&N air filter. they make a stock replacement filter that works with the stock air cleaner assembly. A low flow performance exhaust cat back system is the next logical step. This car doesn't have a real on board computer like today's cars, so chipping it is out. There are however performance upgrades you can make to the CISE fuel injection system. Really other than going to the expense of adding a turbo or rebuilding the engine with performance goodies like a cam and such, there's not a whole lot more than that. Your car will run its best and keep you on the road with more trouble free miles if you keep your expectations and your modification on the low side. The simple exhaust and air filter upgrades will be enough for you to see a slight performance and mpg increase. Good luck
18L per 100km equates to 13 miles per gallon!
It is a V-8 18L
18 l is greater.
There are 36 units of 250 ml in 18 litre
if u havn't changed the fuel filter that might be a place to start Have you tried checking the lambada probe?
Use the radio's volume and frequesce setting buttons next to the clock.
Nissan 18L can you put super4 spark plugs
there is no difference unless you are referring to the Northrop Grumman F-18L and the McDonnell Douglas F/A-18
I found this site, http://installdr.com/InstallDocs/Acura/Integra.html, hope it helps.
The width of the room is equal to twice the Length. Suppose Length = L, width = W, and A = areaW = 2L from the information in the questionNow we know area, A is equal to length times widthW*L=A, plug in 2L for W and we get 2L*L=A or 2L^2=ANext, we see that when 6 is subtracted from both length and width A becomes 108 less.So (2L-6)*(L-6)=A-108Multiply (2L-6)*(L-6) out and the result is (2L^2-18L+36) Set that equal to A-108(2L^2-18L+36)=A-108. We found out that A=2L^2 earlier so we can substitute the terms.(2L^2-18L+36)=2L^2-108. Now solve for LSubtract 2L^2 from both sides(-18L+36)=(-108)Subtract 36 from both sides(-18L)=(-144)Divide by (-18)L=8We know W=2L so W=16Now lets test our answer.16*8=128(16-6)*(8-6)=10*2=20128-20=108So the answer of L=8 and W=16 is correct.
18000mL is 18L (divide mL by 1,000).1800 ml = 1. 8 liter
Three minutes from the time the first aircraft takes off.